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zjc1987

½ð³æ (ÖøÃûдÊÖ)

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justdoit
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zaq123321

ר¼Ò¹ËÎÊ (ÖøÃûдÊÖ)

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zjc1987: ½ð±Ò+10, ¡ïÓаïÖú 2015-03-25 23:13:38
Not necessarily. Suppose A is Zero matrix. It will be not possible. Btw, I need to revisit my answer to your last question.

[ ·¢×ÔÊÖ»ú°æ http://muchong.com/3g ]
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2Â¥2015-03-25 18:22:22
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feixiaolin

ÈÙÓþ°æÖ÷ (ÎÄ̳¾«Ó¢)

ÓÅÐã°æÖ÷

×î¼ò´ð°¸  k=1
3Â¥2015-03-29 11:13:07
ÒÑÔÄ   »Ø¸´´ËÂ¥   ¹Ø×¢TA ¸øTA·¢ÏûÏ¢ ËÍTAºì»¨ TAµÄ»ØÌû

zjc1987

½ð³æ (ÖøÃûдÊÖ)

ÒýÓûØÌû:
3Â¥: Originally posted by feixiaolin at 2015-03-29 11:13:07
×î¼ò´ð°¸  k=1

k=1ÊDz»Ðеģ¬ÎÒÒªµÄÊÇÁÐÂúÖÈ
justdoit
4Â¥2015-03-29 12:51:44
ÒÑÔÄ   »Ø¸´´ËÂ¥   ¹Ø×¢TA ¸øTA·¢ÏûÏ¢ ËÍTAºì»¨ TAµÄ»ØÌû

hank612

ÖÁ×ðľ³æ (ÖøÃûдÊÖ)

ÓÉÓÚ rank(A,0; *,B) >= rank(A) + rank(B), (*±íʾÈÎÒâ¾ØÕó), ËùÒÔÒ»µ©Ä³¸öM_sÊÇÁÐÂúÖȵÄ, ÄÇôÒÔºóµÄM_r (r>s)¶¼ÊÇÁÐÂúÖÈ.

ÓÉÓÚA=0, A=1¶¼½«Ê¹µÃM_k²»ÊÇÁÐÂúÖÈ, ËùÒÔÎҲ²â: Èç¹û A ´æÔÚÓзÇÁã·ÇÒ»µÄµÄÌØÕ÷Öµ, ÄÇôM_k×îÖÕÊÇÁÐÂúÖȵÄ. ²»¹ý, ÎÒÖ¤Ã÷²»³öÀ´.
We_must_know. We_will_know.
5Â¥2015-04-09 07:06:50
ÒÑÔÄ   »Ø¸´´ËÂ¥   ¹Ø×¢TA ¸øTA·¢ÏûÏ¢ ËÍTAºì»¨ TAµÄ»ØÌû

junefi

Ìú¸Ëľ³æ (ÕýʽдÊÖ)

Ëͺ컨һ¶ä
If (A,C) is unobservable, i.e., rank[C', A'C', ..., {A^{n-1}}'C']'<n, then there exists a non-zero vector, say v, such that [C', A'C', ..., {A^{n-1}}'C']'*v=0. Let w=[v; 0; ... ;0], then we have M_i*w=0 for all i=1,...,n-1.
Therefore, a necessary condition for that there exists k such that M_k is full column rank is that (A,C) is observable.
ÀíÂ۸ıäÊÀ½ç£¡
6Â¥2015-04-09 10:25:12
ÒÑÔÄ   »Ø¸´´ËÂ¥   ¹Ø×¢TA ¸øTA·¢ÏûÏ¢ ËÍTAºì»¨ TAµÄ»ØÌû

zjc1987

½ð³æ (ÖøÃûдÊÖ)

ÒýÓûØÌû:
6Â¥: Originally posted by junefi at 2015-04-09 10:25:12
If (A,C) is unobservable, i.e., rank'<n, then there exists a non-zero vector, say v, such that '*v=0. Let w=, then we have M_i*w=0 for all i=1,...,n-1.
Therefore, a necessary condition for that t ...

Thank you!  now  we have proven that the necessary conditionof the existence of  M_k is (A,D,C) is strong observable, i.e., for any complex number s,
rank([s*I-A  D; C   0])=n+rank(D). But my interesting in that whether or not the condition  (A,D,C) is strong observable can implies the existence of M_k with full column rank?
justdoit
7Â¥2015-04-09 10:40:26
ÒÑÔÄ   »Ø¸´´ËÂ¥   ¹Ø×¢TA ¸øTA·¢ÏûÏ¢ ËÍTAºì»¨ TAµÄ»ØÌû

zjc1987

½ð³æ (ÖøÃûдÊÖ)

ÒýÓûØÌû:
5Â¥: Originally posted by hank612 at 2015-04-09 07:06:50
ÓÉÓÚ rank(A,0; *,B) >= rank(A) + rank(B), (*±íʾÈÎÒâ¾ØÕó), ËùÒÔÒ»µ©Ä³¸öM_sÊÇÁÐÂúÖȵÄ, ÄÇôÒÔºóµÄM_r (r>s)¶¼ÊÇÁÐÂúÖÈ.

ÓÉÓÚA=0, A=1¶¼½«Ê¹µÃM_k²»ÊÇÁÐÂúÖÈ, ËùÒÔÎҲ²â: Èç¹û A ´æÔÚÓзÇÁã·ÇÒ»µÄµÄÌØ ...

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justdoit
8Â¥2015-04-09 10:42:34
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