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feixiaolin

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ÏȰÑʽ×ÓÕûÀíд³ÉÁ½Ïȷ¶¨³öǰn¸öexp(m/2)*sqrt(1+1/3)*sin(sqrt(3)*m/2)-arctan(sqrt(3)))Ϊ¸ºµÄÇø¼ä£¬½â¾Í²úÉúÔÚÕ⼸¸öÇø¼äÄÚ¡£

[ Last edited by feixiaolin on 2013-12-20 at 15:02 ]
2Â¥2013-12-20 13:20:18
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lihui6751303

Òø³æ (СÓÐÃûÆø)

feixiaolin: ±à¼­ÄÚÈÝ 2013-12-20 14:56
feixiaolin: ±à¼­ÄÚÈÝ 2013-12-20 15:01
ÒýÓûØÌû:
2Â¥: Originally posted by feixiaolin at 2013-12-20 13:20:18
ÏȰÑʽ×ÓÕûÀíд³ÉÁ½Ïȷ¶¨³öǰn¸öexp(m/2)*sqrt(1+1/3)*sin(sqrt(3)*m/2)-arctan(sqrt(3)))Ϊ¸ºµÄÇø¼ä£¬½â¾Í²úÉúÔÚÕ⼸¸öÇø¼äÄÚ¡£

Äܲ»ÄܾßÌåµÄ˵Ã÷£¬»òÕßÓÃWordÎĵµËµÃ÷Ò»ÏÂлл£¡£¡£¡£¡

[ Last edited by feixiaolin on 2013-12-20 at 15:01 ]
Godloveme
3Â¥2013-12-20 13:35:27
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feixiaolin

ÈÙÓþ°æÖ÷ (ÎÄ̳¾«Ó¢)

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ÒýÓûØÌû:
3Â¥: Originally posted by lihui6751303 at 2013-12-20 13:35:27
Äܲ»ÄܾßÌåµÄ˵Ã÷£¬»òÕßÓÃWordÎĵµËµÃ÷Ò»ÏÂлл£¡£¡£¡£¡
...

ԭʽ£¬ºóÁ½ÏîÌá³ö¹«Òò×Óexp(m/2)£¬
д³É sinA*cosB+cosA*sinBµÄÐÎʽ£¬ÓÐ
exp(m/2)*sqrt(1+1/3)*sin(sqrt(3)*m/2)-arctan(sqrt(3)))=0
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exp(-m)+exp(m/2)*sqrt(1+1/3)*sin(sqrt(3)*m/2)-arctan(sqrt(3)))=0
exp(-m)>0,
¹Ê±ØÐëÈ¡  exp(m/2)*sqrt(1+1/3)*sin(sqrt(3)*m/2)-arctan(sqrt(3)))<0 µÄÇø¼ä
4Â¥2013-12-20 15:02:00
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dingd

Ìú¸Ëľ³æ (Ö°Òµ×÷¼Ò)

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feixiaolin: ½ð±Ò+2, ¸ÐлӦÖú¡£ 2013-12-20 15:30:09
¿ÉÒÔÊÓ×÷´øµÈÊ½Ô¼ÊøµÄ×îСֵÎÊÌâÀ´Çó½â£º
CODE:
ParameterDomain = [0,];
MinFunction m;
exp(-m)-exp(m/2)*cos(sqrt(3)*m/2)+sqrt(3)/3*exp(m/2)*sin(sqrt(3)*m/2)=0;

È總ͼ£¬Èç¹û0ËãµÄ»°£¬×îСֵ¾ÍÊÇm=0£¬·ñÔò¾ÍÊÇm=0.976487274831026

Ä¿±êº¯ÊýÖµ(×îС): 0.976487274831026
m: 0.976487274831026

Ô¼Êøº¯Êý:
   1: exp(-m)-exp(m/2)*cos(sqrt(3)*m/2)+sqrt(3)/3*exp(m/2)*sin(sqrt(3)*m/2)-(0) = -4.849376456E-011
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5Â¥2013-12-20 15:17:42
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feixiaolin

ÈÙÓþ°æÖ÷ (ÎÄ̳¾«Ó¢)

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Сľ³æ: ½ð±Ò+0.5, ¸ø¸öºì°ü£¬Ð»Ð»»ØÌû
ÒýÓûØÌû:
5Â¥: Originally posted by dingd at 2013-12-20 15:17:42
¿ÉÒÔÊÓ×÷´øµÈÊ½Ô¼ÊøµÄ×îСֵÎÊÌâÀ´Çó½â£º

ParameterDomain = ;
MinFunction m;
exp(-m)-exp(m/2)*cos(sqrt(3)*m/2)+sqrt(3)/3*exp(m/2)*sin(sqrt(3)*m/2)=0;


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lihui6751303

Òø³æ (СÓÐÃûÆø)

ллÕâλÅóÓÑ£¡ÄãÓõÄÊÇMatlab»¹ÊÇMathematical?
Godloveme
7Â¥2013-12-20 16:44:42
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lihui6751303

Òø³æ (СÓÐÃûÆø)

ÔõôÊäÈëÔÚMathematicalÄã¸øµÄCODE:
ParameterDomain = [0,];
MinFunction m;
exp(-m)-exp(m/2)*cos(sqrt(3)*m/2)+sqrt(3)/3*exp(m/2)*sin(sqrt(3)*m/2)=0;
ÓдíÎóÄØ£¿ÔËÐв»³öÀ´°¡£¿
Godloveme
8Â¥2013-12-20 17:09:00
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dingd

Ìú¸Ëľ³æ (Ö°Òµ×÷¼Ò)

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9Â¥2013-12-20 18:51:54
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lihui6751303

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  • 2013-12-20 19:41:45, 16 K
Godloveme
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