| 查看: 1370 | 回复: 5 | ||
chaofan1231银虫 (小有名气)
|
[求助]
matlab解代数方程的问题
|
|
|
哪位大侠帮忙看下这是怎么回事啊?谢谢啊 y=2; >> subs(solve('y=exp((1/0.0000005461-1/0.000000700)*0.014388/x+ln((x-993.74731)/2869.03078)-5*ln(700/546.1))','x')) Warning: Explicit solution could not be found. 我把y=2直接代进去的话solve('2=exp((1/0.0000005461-1/0.000000700)*0.014388/x+ln((x-993.74731)/2869.03078)-5*ln(700/546.1))','x') ans =matrix([[14197.808632879686391435779145547]]),但是我在origin中将这个方程画成曲线的话,y=2时x的两个值分别在1100和1900附近,这是怎么回事啊? |
» 猜你喜欢
博士去二本高校当辅导员,如何调整心态?
已经有8人回复
27细胞生物学申博
已经有5人回复
面上有专家说实验设备不是我们单位的
已经有5人回复
江苏省自然基金 什么时候出结果
已经有6人回复
广西大学-广州大学招聘博士后 欢迎广大优秀人才!!!
已经有11人回复
闲聊
已经有3人回复
如何查询2026年获批项目名称?
已经有3人回复
两块石头
已经有10人回复
售SCI一区T0P文章,我:8O.55.1.O.54,科目全,可伽急
已经有15人回复
面上没中,邀请各位路过的虫友分析一下分数
已经有13人回复
» 本主题相关价值贴推荐,对您同样有帮助:
求matlab 解方程的问题
已经有5人回复
【活动】学习软件,推荐书活动(有BB奖励哟)
已经有51人回复
【求助】高维PDE的求解
已经有11人回复
【答案】应助回帖
★ ★ ★ ★ ★
chaofan1231: 金币+5, ★★★★★最佳答案 2012-05-15 14:53:43
chaofan1231: 回帖置顶 2012-05-15 14:54:44
chaofan1231: 金币+5, ★★★★★最佳答案 2012-05-15 14:53:43
chaofan1231: 回帖置顶 2012-05-15 14:54:44
|
>> evalin(symengine, 'numeric::solve(2=exp((1/0.0000005461-1/0.000000700)*0.014388/x+ln((x-993.74731)/2869.03078)-5*ln(700/546.1)), x = 1000..2000)') ans = 1092.7957902606343947864233870012 >> evalin(symengine, 'numeric::solve(2=exp((1/0.0000005461-1/0.000000700)*0.014388/x+ln((x-993.74731)/2869.03078)-5*ln(700/546.1)), x = 1500..2000)') ans = 1826.2296709384982930177909403237 Solve the following equation: syms x; solve('sin(x) = x^2 - 1') The symbolic solver cannot find an exact symbolic solution for this equation, and therefore, it calls the numeric solver. Because the equation is not polynomial, an attempt to find all possible solutions can take a long time. The numeric solver does not try to find all numeric solutions for this equation. Instead, it returns only the first solution that it finds: ans = -0.63673265080528201088799090383828 Plotting the left and the right sides of the equation in one graph shows that the equation also has a positive solution: ezplot(sin(x), -2, 2); hold on; ezplot(x^2 - 1, -2, 2) hold off You can find this solution by calling the MuPAD numeric solver directly and specifying the interval where this solution can be found. To call MuPAD commands from the MATLAB Command Window, use the evalin or feval function: evalin(symengine, 'numeric::solve(sin(x) = x^2 - 1, x = 0..2)') ans = 1.4096240040025962492355939705895 |
» 本帖已获得的红花(最新10朵)

5楼2012-05-15 09:18:57

2楼2012-05-14 10:01:04

3楼2012-05-14 10:01:30
chaofan1231
银虫 (小有名气)
- 应助: 29 (小学生)
- 金币: 1599
- 帖子: 240
- 在线: 89.3小时
- 虫号: 1243032
- 注册: 2011-03-23
- 性别: GG
- 专业: 资源化工
4楼2012-05-15 08:05:50
chaofan1231
银虫 (小有名气)
送鲜花一朵
|
6楼2012-05-15 14:54:04










回复此楼
是这样的,但是为什么matlab中解出来只有一个解?我想要的是前两个。