function dy=pmb2(t,y)
arf=19.4;
RR=0.995;
L=0.05;
kxi=(log(1/RR)+L)/L;
N=4.5;
A=-int(y(1),0,t);
dy=zeros(3,1);
dy(1)=dy(1)*N*exp(A)-y(1)-arf*y(1)*y(2);
dy(2)=arf*y(2)*y(1)-kxi*y(2);

4楼: Originally posted by NaraEllen at 2020-06-26 17:29:18
大神，可以展开讲讲这个积分微分方程怎么用拉普拉斯变换吗？