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First PW12 (2.88 g) was dissolved in ...

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First PW12 (2.88 g) was dissolved in water (10 mL) and the pH of the solution was adjusted to 4.8 using NaHCO3 solution. This resulted in the formation of lacunary heteropoly anion [PW11O39]7. The solution having pH 4.8 was heated to 90 C with constant stirring. Then to it a solution of Co(NO3)26H2O (0.29 g) in water (10 mL) was added. The NaCoPW11 was obtained by solvent evaporation, and recrystallization from water, followed by subsequent drying at 110 C for 12 h
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First PW12 (2.88 g) was dissolved in water (10 mL) and the pH of the solution was adjusted to 4.8 using NaHCO3 solution. This resulted in the formation of lacunary heteropoly anion [PW11O39]7. The solution having pH 4.8 was heated to 90 C with constant stirring. Then to it a solution of Co(NO3)26H2O (0.29 g) in water (10 mL) was added. The NaCoPW11 was obtained by solvent evaporation, and recrystallization from water, followed by subsequent drying at 110 C for 12 h

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The volume is then reduced to half by evaporation and the heteropolyanion separated in a dense lower layer by liquid-liquid extraction with 80-100 mL of acetone. The extraction is repeated until the acetone extract shows no nitric ions (ferrous sulfate test).
The solid sodium salt is obtained as the hydrate (15-20H,O) by evaporation to dryness (in air) of the acetone extracts.
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6Â¥: Originally posted by woodkeeper at 2014-03-13 18:01:41
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First PW12 (2.88 g) was dissolved in water (10 mL) and the pH of the solution was adjusted to 4.8 using NaHCO3 solution. This resulted in the formation of lacunary heteropoly anion [PW11O39]7. The solution having pH 4.8 was heated to 90 C with constant stirring. Then to it a solution of Co(NO3)26H2O (0.29 g) in water (10 mL) was added. The NaCoPW11 was obtained by solvent evaporation, and recrystallization from water, followed by subsequent drying at 110 C for 12 h
10Â¥2014-03-13 20:10:53
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