应《网络安全法》要求，自2017年10月1日起，未进行实名认证将不得使用互联网跟帖服务。为保障您的帐号能够正常使用，请尽快对帐号进行手机号验证，感谢您的理解与支持！

24小时热门版块排行榜    

小木虫论坛-学术科研互动平台 » 计算模拟区 » 计算模拟 » 求解高次复杂函数
51/1返回列表
查看: 1464  |  回复: 11
只看楼主 @他人 存档 新回复提醒 (忽略) 收藏    在APP中查看
当前只显示满足指定条件的回帖，点击这里查看本话题的所有回帖

denmarkrico

银虫 (小有名气)

[求助] 求解高次复杂函数 已有3人参与

求解下面这个高次方程时为什么总是得到虚数解，我所用的是MATLAB2012b版

syms h c l theta11 theta21 theta31 x
h=14.5;
l=55.5;
c=19.73;
theta11=0.01/37;
theta21=0.035/37;
theta31=0.065/37;
F=((3*c + 3*h - (433*l)/250 + 2*l*cos(theta11) +3^(1/2)*c*sin(theta0) - c*cos(theta0) +l*cos(theta21) + 3^(1/2)*l*sin(theta21) + (2*c*(x^2 - 1))/(x^2 + 1))*(2*l^2*(sin(theta11) - 1) - 2*l^2*(sin(theta31) - 1) + 2*c*(c + h) - 2*c*l*cos(theta11) - 2*l*cos(theta11)*(c + h) + 2*l*cos(theta31)*(c + h) + 2*c*l*cos(theta0)*cos(theta31) - 2*c*l*sin(theta0)*sin(theta31) - (4*c*l*x)/(x^2 + 1) + (2*c*(c + h)*(x^2 - 1))/(x^2 + 1)) + (3*c + 3*h + (433*l)/250 + 2*l*cos(theta11) + l*cos(theta31) - c*cos(theta0) - 3^(1/2)*c*sin(theta0) - 3^(1/2)*l*sin(theta31) + (2*c*(x^2 - 1))/(x^2 + 1))*(2*l^2*(sin(theta21) - 1) - 2*l^2*(sin(theta11) - 1) - 2*c*(c + h) + 2*c*l*cos(theta11) + 2*l*cos(theta11)*(c + h) - 2*l*cos(theta21)*(c + h) + (4*c*l*x)/(x^2 + 1) - (2*c*(c + h)*(x^2 - 1))/(x^2 + 1) + (4*c*l*x*sin(theta21))/(x^2 + 1) + (2*c*l*cos(theta21)*(x^2 - 1))/(x^2 + 1)))^2 + (((433*c)/250 + (433*h)/250 + 3*l + 2*l*sin(theta11) + 2*l*sin((2*pi)/3 + theta21) - (2*c*x)/(x^2 + 1) - (3^(1/2)*c*(x^2 - 1))/(x^2 + 1))*(2*l^2*(sin(theta11) - 1) - 2*l^2*(sin(theta31) - 1) + 2*c*(c + h) - 2*c*l*cos(theta11) - 2*l*cos(theta11)*(c + h) + 2*l*cos(theta31)*(c + h) - (4*c*l*x)/(x^2 + 1) + (2*c*(c + h)*(x^2 - 1))/(x^2 + 1) + (4*c*l*x*sin(theta31))/(x^2 + 1) - (2*c*l*cos(theta31)*(x^2 - 1))/(x^2 + 1)) - ((433*c)/250 + (433*h)/250 - 3*l + 2*l*sin(theta11) +c*sin(theta0) + l*sin(theta31) + 3^(1/2)*l*cos(theta31) - 3^(1/2)*c*cos(theta0) + (4*c*x)/(x^2 + 1))*(2*l^2*(sin(theta21) - 1) - 2*l^2*(sin(theta11) - 1) - 2*c*(c + h) + 2*c*l*cos(theta11) + 2*l*cos(theta11)*(c + h) - 2*l*cos(theta21)*(c + h) + (4*c*l*x)/(x^2 + 1) - (2*c*(c + h)*(x^2 - 1))/(x^2 + 1) + (4*c*l*x*sin(theta21))/(x^2 + 1) + (2*c*l*cos(theta21)*(x^2 - 1))/(x^2 + 1)))^2 + ((3*c + 3*h - (433*l)/250 + 2*l*cos(theta11) + l*cos(theta21) - c*cos(theta0) + 3^(1/2)*c*sin(theta0) + 3^(1/2)*l*sin(theta21) + (2*c*(x^2 - 1))/(x^2 + 1))*((433*c)/250 + (433*h)/250 - 3*l + 2*l*sin(theta11) +c*sin(theta0) + l*sin(theta31) + 3^(1/2)*l*cos(theta31) - 3^(1/2)*c*cos(theta0) + (4*c*x)/(x^2 + 1)) + (3*c + 3*h + (433*l)/250 + 2*l*cos(theta11) + l*cos(theta31) - c*cos(theta0) - 3^(1/2)*c*sin(theta0) - 3^(1/2)*l*sin(theta31) + (2*c*(x^2 - 1))/(x^2 + 1))*((433*c)/250 + (433*h)/250 + 3*l - 2*l*sin(theta11) + 3^(1/2)*l*cos(theta21) - l*sin(theta21) - c*sin(theta0) - 3^(1/2)*c*cos(theta0) - (4*c*x)/(x^2 + 1)))^2*(2*c*h - 2*l^2*(sin(theta11) - 1) + 2*c^2 - 2*c*(c + h) + 2*c*l*cos(theta11) + 2*l*cos(theta11)*(c + h)) + ((((433*c)/250 + (433*h)/250 - 3*l + 2*l*sin(theta11) +c*sin(theta0) + l*sin(theta31) + 3^(1/2)*l*cos(theta31) - 3^(1/2)*c*cos(theta0) + (4*c*x)/(x^2 + 1))*(2*l^2*(sin(theta11) - 1) - 2*l^2*(sin(theta21) - 1) + 2*c*(c + h) - 2*c*l*cos(theta11) - 2*l*cos(theta11)*(c + h) + 2*l*cos(theta21)*(c + h) + 2*c*l*cos(theta0)*cos(theta21) - 2*c*l*sin(theta0)*sin(theta21) - (4*c*l*x)/(x^2 + 1) + (2*c*(c + h)*(x^2 - 1))/(x^2 + 1)) + ((433*c)/250 + (433*h)/250 + 3*l - 2*l*sin(theta11) + 3^(1/2)*l*cos(theta21) - l*sin(theta21) - c*sin(theta0) - 3^(1/2)*c*cos(theta0) - (4*c*x)/(x^2 + 1))*(2*l^2*(sin(theta11) - 1) - 2*l^2*(sin(theta31) - 1) + 2*c*(c + h) - 2*c*l*cos(theta11) - 2*l*cos(theta11)*(c + h) + 2*l*cos(theta31)*(c + h) + 2*c*l*cos(theta0)*cos(theta31) - 2*c*l*sin(theta0)*sin(theta31) - (4*c*l*x)/(x^2 + 1) + (2*c*(c + h)*(x^2 - 1))/(x^2 + 1)))*(2*c + 2*h + 2*l*cos(theta11) + (2*c*(x^2 - 1))/(x^2 + 1)) - ((3*c + 3*h + (433*l)/250 + 2*l*cos(theta11) + l*cos(theta31) - c*cos(theta0) - 3^(1/2)*c*sin(theta0) - 3^(1/2)*l*sin(theta31) + (2*c*(x^2 - 1))/(x^2 + 1))*(2*l^2*(sin(theta11) - 1) - 2*l^2*(sin(theta21) - 1) + 2*c*(c + h) - 2*c*l*cos(theta11) - 2*l*cos(theta11)*(c + h) + 2*l*cos(theta21)*(c + h) + 2*c*l*cos(theta0)*cos(theta21) - 2*c*l*sin(theta0)*sin(theta21) - (4*c*l*x)/(x^2 + 1) + (2*c*(c + h)*(x^2 - 1))/(x^2 + 1)) - (3*c + 3*h - (433*l)/250 + 2*l*cos(theta11) +l*cos(theta21) - c*cos(theta0) + 3^(1/2)*c*sin(theta0) + 3^(1/2)*l*sin(theta21) + (2*c*(x^2 - 1))/(x^2 + 1))*(2*l^2*(sin(theta11) - 1) - 2*l^2*(sin(theta31) - 1) + 2*c*(c + h) - 2*c*l*cos(theta11) - 2*l*cos(theta11)*(c + h) + 2*l*cos(theta31)*(c + h) + 2*c*l*cos(theta0)*cos(theta31) - 2*c*l*sin(theta0)*sin(theta31) - (4*c*l*x)/(x^2 + 1) + (2*c*(c + h)*(x^2 - 1))/(x^2 + 1)))*(2*l*sin(theta11) - 2*l + (4*c*x)/(x^2 + 1)))*((3*c + 3*h - (433*l)/250 + 2*l*cos(theta11) + l*cos(theta21) + 3^(1/2)*l*sin(theta21) + (3*c*(x^2 - 1))/(x^2 + 1) + (2*3^(1/2)*c*x)/(x^2 + 1))*((433*c)/250 + (433*h)/250 - 3*l + 2*l*sin(theta11) - l*sin(theta31) + 3^(1/2)*l*cos(theta31) + (2*c*x)/(x^2 + 1) - (3^(1/2)*c*(x^2 - 1))/(x^2 + 1)) + (3*c + 3*h + (433*l)/250 + 2*l*cos(theta11) + l*cos(theta31) - c*cos(theta0) - 3^(1/2)*c*sin(theta0) - 3^(1/2)*l*sin(theta31) + (2*c*(x^2 - 1))/(x^2 + 1))*((433*c)/250 + (433*h)/250 + 3*l - 2*l*sin(theta11) + 3^(1/2)*l*cos(theta21) - l*sin(theta21) - c*sin(theta0) - 3^(1/2)*c*cos(theta0) - (4*c*x)/(x^2 + 1)))；
回复此楼

» 猜你喜欢

» 本主题相关价值贴推荐，对您同样有帮助:
心 那个凉啊
1楼 2013-12-13 22:28:48
已阅   回复此楼   关注TA 给TA发消息 送TA红花 TA的回帖

denmarkrico

银虫 (小有名气)
送红花一朵
引用回帖:
2楼: Originally posted by feixiaolin at 2013-12-13 22:53:29
1）theta0 待求还是已知？
2）取y1=(x^2 - 1))/(x^2 + 1);
        y2=x/(x^2 + 1);
     先求y1, y2，最后求 x如何？

你这个替代法我见过
赞一下 回复此楼
心 那个凉啊
6楼2013-12-14 16:07:30
已阅   回复此楼   关注TA 给TA发消息 送TA红花 TA的回帖
查看全部 12 个回答

feixiaolin

荣誉版主 (文坛精英)

优秀版主

【答案】应助回帖

感谢参与，应助指数 +1
1）theta0 待求还是已知？
2）取y1=(x^2 - 1))/(x^2 + 1);
        y2=x/(x^2 + 1);
     先求y1, y2，最后求 x如何？
赞一下(1人) 回复此楼

» 本帖已获得的红花（最新10朵）

denmarkrico
2楼2013-12-13 22:53:29
已阅   回复此楼   关注TA 给TA发消息 送TA红花 TA的回帖

jerkwin

专家顾问 (正式写手)
你这方程, 能解出来我觉得很奇怪
赞一下 回复此楼
3楼2013-12-13 23:10:14
已阅   回复此楼   关注TA 给TA发消息 送TA红花 TA的回帖

paopaoai11

木虫 (小有名气)
你这什么方程啊？

[ 发自小木虫客户端 ]
回复此楼
泡泡
4楼2013-12-14 01:03:00
已阅   回复此楼   关注TA 给TA发消息 送TA红花 TA的回帖
查看全部 12 个回答
普通表情 龙 兔 虎 猫
最具人气热帖推荐 [查看全部] 作者 回/看 最后发表
[考研] 一志愿吉林大学材料学硕321求调剂 +9 Ymlll 2026-03-18 12/600 2026-03-20 00:01 by 23Postgrad
[考研] 梁成伟老师课题组欢迎你的加入 +9 一鸭鸭哟 2026-03-14 11/550 2026-03-19 17:22 by ！本暗一次！
[考研] 复试调剂 +4 z1z2z3879 2026-03-14 6/300 2026-03-19 17:18 by fei626-918
[考研] 【考研调剂】化学专业 281分，一志愿四川大学，诚心求调剂 +5 吃吃吃才有意义 2026-03-19 5/250 2026-03-19 16:18 by 30660438
[考研] 085601材料工程专硕求调剂 +10 慕寒mio 2026-03-16 10/500 2026-03-19 15:26 by 丁丁*
[考研] 求调剂 +3 Mqqqqqq 2026-03-19 3/150 2026-03-19 14:11 by peike
[考研] 求调剂，一志愿:南京航空航天大学大学 ，080500材料科学与工程学硕，总分289分 +3 @taotao 2026-03-19 3/150 2026-03-19 14:07 by peike
[考研] 328求调剂，英语六级551，有科研经历 +4 生物工程调剂 2026-03-16 12/600 2026-03-19 11:10 by 生物工程调剂
[考研] 一志愿天大材料与化工（085600）总分338 +5 蔡大美女 2026-03-13 5/250 2026-03-19 10:44 by 是小刘呀～
[考研] 070300化学319求调剂 +6 锦鲤0909 2026-03-17 6/300 2026-03-18 13:22 by Iveryant
[考研] 326求调剂 +5 上岸的小葡 2026-03-15 6/300 2026-03-17 17:26 by ruiyingmiao
[考研] 考研化学学硕调剂，一志愿985 +4 张vvvv 2026-03-15 6/300 2026-03-17 17:15 by ruiyingmiao
[考研] 308求调剂 +4 是Lupa啊 2026-03-16 4/200 2026-03-17 17:12 by ruiyingmiao
[考研] 材料与化工专硕调剂 +5 heming3743 2026-03-16 5/250 2026-03-17 14:03 by 勇敢太监王公公
[考研] 材料工程专硕274一志愿211求调剂 +6 薛云鹏 2026-03-15 6/300 2026-03-17 11:05 by 学员h26Tkc
[考研] 304求调剂 +3 曼殊2266 2026-03-14 3/150 2026-03-16 16:39 by houyaoxu
[考研] 321求调剂 +5 大米饭！ 2026-03-15 5/250 2026-03-16 16:33 by houyaoxu
[考研] 0703化学调剂 290分有科研经历，论文在投 +7 腻腻gk 2026-03-14 7/350 2026-03-16 10:12 by houyaoxu
[考研] 求老师收留调剂 +4 jiang姜66 2026-03-14 5/250 2026-03-15 20:11 by Winj1e
[考研] 一志愿哈工大材料324分求调剂 +5 闫旭东 2026-03-14 5/250 2026-03-14 14:53 by 木瓜膏
信息提示
关闭
请填处理意见
关闭