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dv/dt=g-A*v^2=g*(1-A/g*v^2)
dv/(1-A/g*v^2)=g*dt
{1/[1-sqrt(A/g)*v]+1/[1+sqrt(A/g)*v]}*dv=2*g*dt
Ln{[1+sqrt(A/g)*v]/[1-sqrt(A/g)*v]}=2*g*sqrt(A/g)*t + LnC
ÓÉt=0 v=0´úÈëÉÏʽµÃµ½C=1
[1+sqrt(A/g)*v]/[1-sqrt(A/g)*v]}=exp{2*sqrt(A*g)*t}
v=sqrt(g/A)*sh[sqrt(A*g)*t]/ch[sqrt(A*g)*t]
2Â¥2016-06-13 14:51:25
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3Â¥2016-06-13 21:38:29
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qiusuozhong

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3Â¥: Originally posted by aprillf at 2016-06-13 21:38:29
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\sqrt{\frac{g}{A}}\tanh\left(\left({\color{red}C_1}+t\right)\sqrt{gA}\right)

tanh ±íʾ˫ÇúÕýÇÐ tanh(x)=£¨e^x-e^-x£©/(e^x+e^-x)

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5Â¥2016-06-15 09:45:58
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qiusuozhong

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ÒýÓûØÌû:
2Â¥: Originally posted by peterflyer at 2016-06-13 14:51:25
dv/dt=g-A*v^2=g*(1-A/g*v^2)
dv/(1-A/g*v^2)=g*dt
{1/+1/}*dv=2*g*dt
Ln{/}=2*g*sqrt(A/g)*t + LnC
ÓÉt=0 v=0´úÈëÉÏʽµÃµ½C=1
/}=exp{2*sqrt(A*g)*t}
v=sqrt(g/A)*sh/ch...

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