2Â¥: Originally posted by
hank612 at 2015-04-10 06:14:57
ÄãÈ·¶¨Õâ¸ö·½³ÌÓÐ(Laurent)¼¶Êý½âô?
Èç¹ûÈÃg(x)=\sum_{k=0}^{\infty}\frac{x^{6^k}}{6^k}, ÓÉÓÚ g(z^6)=6g(z)-6z.
ÈÃh(x)=f(x)-\frac{g^2(x)}{2}, Á¢µÃ:
h(x^6)-6h(x)=-6xg(x)-39x^2-\frac{2}{x^3}
¼´Ê¹Óà ...