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jabile
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2Â¥2013-11-10 12:23:40
hank612
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felix2018: ½ð±Ò+2, ¡ï¡ï¡ïºÜÓаïÖú 2013-11-12 17:27:57
¸Ðл²ÎÓ룬ӦÖúÖ¸Êý +1
felix2018: ½ð±Ò+2, ¡ï¡ï¡ïºÜÓаïÖú 2013-11-12 17:27:57
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my answer is slightly different from Jabile's answer. Lou2 Zhu3 make your own decision. Let Pn be the prob of occurrence of red color being even, then by consider the first element is red or not, we obtain that P(n)= 1/3 * (1-P(n-1)) + 2/3* P(n-1) = 1/3 ( 1+ P(n-1)). Clearly P(1) = 2/3. Therefore P(n)= 1/2 * ( 1+ 3^{-n} ) can be checked directly. |

3Â¥2013-11-12 10:33:00
felix2018
Ìú¸Ëľ³æ (ÕýʽдÊÖ)
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- ×¢²á: 2013-10-19
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4Â¥2013-11-12 17:24:51














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