2楼: Originally posted by Mr__Right at 2016-10-10 14:48:51
如果 R(r) 是要求的函数，

R(r)=\dfrac{e^{-r\sqrt{-\dfrac{\lambda}{\alpha}}}\left(\dfrac{C_2e^{2r\sqrt{-\dfrac{\lambda}{\alpha}}}}{\sqrt{-\dfrac{\lambda}{\alpha}}}+2C_1\right)}{2r}...

2楼: Originally posted by Mr__Right at 2016-10-10 14:48:51
如果 R(r) 是要求的函数，

R(r)=\dfrac{e^{-r\sqrt{-\dfrac{\lambda}{\alpha}}}\left(\dfrac{C_2e^{2r\sqrt{-\dfrac{\lambda}{\alpha}}}}{\sqrt{-\dfrac{\lambda}{\alpha}}}+2C_1\right)}{2r}...

5楼: Originally posted by 哈哈笑泥 at 2016-10-10 23:07:21
r很小时，第三项不要，得到解R1
r很大时，第二项不要，得到解R2
设R=R1*R2*u(r)代入求解u(r)，试探！

4楼: Originally posted by ziyuxuanhuan at 2016-10-10 19:53:11
你好，可不可以说说过程？...

3楼: Originally posted by Mr__Right at 2016-10-10 14:54:33
简单一点，

R(r)=\dfrac{1}{r}\left(C_1\;e^{r\sqrt{-\dfrac{\lambda}{\alpha}}}+C_2\;e^{-r\sqrt{-\dfrac{\lambda}{\alpha}}}\right)...

4楼: Originally posted by ziyuxuanhuan at 2016-10-10 19:53:11
你好，可不可以说说过程？...