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wang1273

铁虫 (正式写手)

应助: 0 (幼儿园)
金币: 120.4
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在线: 138.1小时
虫号: 928886
注册: 2009-12-15
专业: 分析仪器与试剂

[求助] 帮忙看一段程序

程序的目的是打开*.txt文件并把数据放入矩阵中，下面是编写的程序，其中 if row*col+2==rdata这个条件能成立吗，是什么意思？非常感谢！（*.txt文件的内容附在后面）。
%打开文件，读取数据
[Filename,Pathname]=uigetfile('*.txt','请打开数据文件');
fid=fopen([Pathname Filename],'r');
[data,count]=fscanf(fid,'%f,%f',inf);
fclose(fid);
%**********************判断数据是否正确*********************************
[rdata,ldata]=size(data);
row=data(1,1);
col=data(2,1);
if ~(rdata)==0
if  row*col+2==rdata
      fprintf('\n\n^_^ ^_^ ^_^ ^_^ ^_^ ^_^ ^_^ ^_^ ^_^ ^_^ ^_^ ^_^\n');
      fprintf('          @数据导入成功！@\n');
      fprintf('       矩阵的维数为%dx%d\n\n',row,col);
      fprintf('^_^ ^_^ ^_^ ^_^ ^_^ ^_^ ^_^ ^_^ ^_^ ^_^ ^_^ ^_^\n\n');
else
      fprintf('\n\nvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv\n');
      fprintf('          @数据文件格式错误！@\n');
      fprintf('vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv\n\n');
      break;
end
else
fprintf('\nvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv\n');
fprintf('             @文件打开失败!@\n');
fprintf('vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv\n\n');
break;
end
11995.64035,0.84427
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11498.07199,0.75842

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1楼 2013-09-12 16:58:42

已阅回复此楼关注TA 给TA发消息送TA红花 TA的回帖

wang1273

铁虫 (正式写手)

应助: 0 (幼儿园)
金币: 120.4
散金: 3
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注册: 2009-12-15
专业: 分析仪器与试剂

引用回帖:

2楼: Originally posted by baobiao007 at 2013-09-12 17:42:00
从你的代码来看，文件数据非常简单，就是两列数值。这种情况下不要用 fopen fprintf 之类的低级文件IO函数。直接用load即可，装入的矩阵自动为两列的，每列对应你的文件的每列数据

那我要调用好多个文件怎么用load函数呢？