10Â¥: Originally posted by Ãæ°üÀ¶µ÷ at 2015-10-29 13:08:21
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1Â¥: Originally posted by Ãæ°üÀ¶µ÷ at 2015-10-28 20:23:00
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3Â¥: Originally posted by simonrac at 2015-10-28 22:05:08
\psi(x) = \int dp \exp{ipx} \psi(p)

V(p) = \int \exp{-ipx} V(x)  dx

In momentum representation :

\frac{p^2}{2m} \psi(p) + \int dp^{\prime} V(p-p^{\prime}) \psi(p^{\prime}) = E \psi(p)

\h ...

4Â¥: Originally posted by simonrac at 2015-10-28 22:08:27
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6Â¥: Originally posted by gh1058 at 2015-10-29 08:52:30
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5Â¥: Originally posted by Ãæ°üÀ¶µ÷ at 2015-10-29 08:30:33
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9Â¥: Originally posted by simonrac at 2015-10-29 11:13:52
ÄãÊDz»ÊÇÒÔΪ´øÓлý·ÖµÄÕâÖÖ \int dp^{\prime} V(p-p^{\prime}) \psi(p^{\prime}) ¾Í²»ÊDZ¾Õ÷·½³ÌÁË£¡

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