3楼: Originally posted by simonrac at 2015-10-28 22:05:08
\psi(x) = \int dp \exp{ipx} \psi(p)

V(p) = \int \exp{-ipx} V(x)  dx

In momentum representation :

\frac{p^2}{2m} \psi(p) + \int dp^{\prime} V(p-p^{\prime}) \psi(p^{\prime}) = E \psi(p)

\h ...

5楼: Originally posted by 面包蓝调 at 2015-10-29 08:30:33
带入以后两侧还是有积分的，该怎么说，可以直接拿掉吗
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10楼: Originally posted by 面包蓝调 at 2015-10-29 13:08:21
我是看了你的前两个式子直接带入后求的，最后变换得到如图，整体有积分，能不能直接拿掉

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11楼: Originally posted by simonrac at 2015-10-29 13:49:57
直接拿掉？ 傅里叶变换的系数你不会求吗？

f(x)=\int dp \exp^{ipx} \frac{p^2}{2m} \psi(p) = \int dp \exp^{ipx} f(p)

f(p)=\frac{p^2}{2m} \psi(p) = \int dx \exp{-ip^{\prime}x} f(x)}

所以你两边同 ...