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李承浩浩

至尊木虫 (著名写手)

[求助] 用matlab画图时为什么出现这种情况? 已有1人参与

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用matlab画图时为什么出现这种情况?
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NicoleLas

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【答案】应助回帖

感谢参与,应助指数 +1
引用回帖:
3楼: Originally posted by 李承浩浩 at 2015-01-24 20:12:31
alpha_1=0.6;
alpha_2=0.6;
p_2=100;
c=60;
pai_0=30;
beta_1=0.3;
beta_2=0.7;
a=0:10:100;
yEES=((alpha_2).^2)*((p_2 -c).^2)./(2*(2*(alpha_2)-(alpha_1).^2 )) - pai_0;
yECS=((alpha_2).^2)*((p_2  ...

yEES是一个标量值,不是向量。计算它的式子不包括a。
Be water, my friend.
4楼2015-01-24 20:46:59
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NicoleLas

木虫 (正式写手)

感觉好奇怪啊!方便贴一下代码不?
Be water, my friend.
2楼2015-01-24 19:17:20
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李承浩浩

至尊木虫 (著名写手)

引用回帖:
2楼: Originally posted by NicoleLas at 2015-01-24 19:17:20
感觉好奇怪啊!方便贴一下代码不?

alpha_1=0.6;
alpha_2=0.6;
p_2=100;
c=60;
pai_0=30;
beta_1=0.3;
beta_2=0.7;
a=0:10:100;
yEES=((alpha_2).^2)*((p_2 -c).^2)./(2*(2*(alpha_2)-(alpha_1).^2 )) - pai_0;
yECS=((alpha_2).^2)*((p_2 -c).^2)./(2*(2*(alpha_2)-(alpha_1).^2 )) + (5*(alpha_2)-2*((alpha_1).^2))*(((1-2*(beta_2))*a).^2)./(2*(alpha_2).*(2*(alpha_2)-((alpha_1).^2))) + (alpha_2)*(p_2 -c)*((1-2*(beta_2))*a)./(2*(alpha_2)-((alpha_1).^2)) - pai_0;
yCES=((alpha_2).^2)*((p_2 -c).^2)./(2*(2*(alpha_2)-(alpha_1).^2 )) + (((1-2*(beta_1))*a).^2)./(alpha_2) - pai_0;
yCCS=((alpha_2).^2)*((p_2 -c).^2)./(2*(2*(alpha_2)-(alpha_1).^2 )) + (5*(alpha_2)-2*((alpha_1).^2))*(((1-2*(beta_2))*a).^2)./(2*(alpha_2).*(2*(alpha_2)-(alpha_1).^2)) + (((1-2*(beta_1))*a).^2)./(alpha_2) + (alpha_2)*(p_2 -c)*(1-2*(beta_2))*a./(2*(alpha_2)-(alpha_1).^2 ) - (2*(1-2*(beta_2)).*a.*(1-2*(beta_1)).*a)./(alpha_2)  -  pai_0;
plot(a,yEES,'b-v',a,yECS,'g-d',a,yCES,'r-o',a,yCCS,'c-s','LineWidth',1.5)
xlabel('a')
ylabel('the profit of the operator')
legend('\pi^{\it EES}_{\it m}','\pi^{\it ECS}_{\it m}','\pi^{\it CES}_{\it m}','\pi^{\it CCS}_{\it m}',2)
axis([0,100,0,3000])
努力!
3楼2015-01-24 20:12:31
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NicoleLas

木虫 (正式写手)

引用回帖:
3楼: Originally posted by 李承浩浩 at 2015-01-24 20:12:31
alpha_1=0.6;
alpha_2=0.6;
p_2=100;
c=60;
pai_0=30;
beta_1=0.3;
beta_2=0.7;
a=0:10:100;
yEES=((alpha_2).^2)*((p_2 -c).^2)./(2*(2*(alpha_2)-(alpha_1).^2 )) - pai_0;
yECS=((alpha_2).^2)*((p_2  ...

比如,假定将yEES改为:
yEES=((alpha_2).^2)*((p_2 -c).^2)./(2*(2*(alpha_2)-(alpha_1).^2 )) - a;画出来的图应该就符合你的要求啦。试一下吧。
Be water, my friend.
5楼2015-01-24 20:50:01
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