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yiyudexiang

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laosam280

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feixiaolin

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2Â¥: Originally posted by laosam280 at 2014-01-03 23:34:19
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dx+dy+dz =0;  µÈ¼ÛÓÚ d(x+y+z)=0   
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z=-(x+y)+constant

[ Last edited by feixiaolin on 2014-1-4 at 17:34 ]
3Â¥2014-01-04 00:11:55
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yiyudexiang

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2Â¥: Originally posted by laosam280 at 2014-01-03 23:34:19
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yiyudexiang

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feixiaolin

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5Â¥: Originally posted by yiyudexiang at 2014-01-07 13:52:20
¶¥°¡¶¥£¬ºÜ¼òµ¥µÄÒ»¸ö·½³Ì°¡£¬ºÃÐÄÈË¿ì³öÏÖ

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x(1.68x+y)/[y(0.23y+x)]=dx/dy= x(1.93*x+y)/[y*(0.28*y+x)]

(1.68x+y)/ (0.23y+x)= (1.93*x+y)/(0.28*y+x)
(0.28*y+x) / (0.23y+x)= (1.93*x+y)/ (1.68x+y)
0.05y/(0.23y+x)=0.25*x/ (1.68x+y)
5*x/y=(1.68x+y)/ (0.23y+x)= (1.68x/y+1)/ (0.23+x/y)
5*(x/y)^2-0.53*(x/y)-1=0
Áîx/y=k£¬Ôò
y=y
x=k*y
z=(1+k)*y+Constant
7Â¥2014-01-08 08:47:23
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