24小时热门版块排行榜    

查看: 1176  |  回复: 2

zhangholmes

至尊木虫 (著名写手)

逍遥门主

[求助] matlab非线性最优化求解,微分方程组的拟合,参数估计

如题,用微分方程组拟合4组不同温度下的数据,求理论值a和b,并使a和b的值分别与实验值y1和y2的差方和最小。并求此时的各个参数值(k1,k2,k3,k4,k5,k6),求各位大侠略施援手。

0<k1<30, 0<k2<10, 0<k3<5, 0<k4<20, 0<k5<20, 0<k6<5
t=[0.494660000000000,0.502760000000000,0.618930000000000,0.621470000000000,0.623470000000000,0.819730000000000,0.825080000000000,0.828350000000000];

T=463 K时,
y1= [0.00800000000000000,0.00990000000000000,0.00782000000000000,0.0108400000000000,0.00937000000000000,0.00882000000000000,0.00614000000000000,0.0108200000000000];
y2=[0.0625100000000000,0.0727400000000000,0.0540300000000000,0.0667600000000000,0.0620200000000000,0.0494400000000000,0.0452000000000000,0.0509400000000000];                                    %y1和y2分别为a和b的实验值

T=473 K时,
y1=[0.00829000000000000,0.0107700000000000,0.00938000000000000,0.0172000000000000,0.0128100000000000,0.0139200000000000,0.0108200000000000,0.0179000000000000];
y2=[0.0622600000000000,0.0719200000000000,0.0525700000000000,0.0604900000000000,0.0586200000000000,0.0444300000000000,0.0405900000000000,0.0439200000000000];

T=483 K时,
y1=[0.0169300000000000,0.0229900000000000,0.0188900000000000,0.0313900000000000,0.0265800000000000,0.0258100000000000,0.0194200000000000,0.0293300000000000];
y2=[0.0537100000000000,0.0598300000000000,0.0431500000000000,0.0465000000000000,0.0450300000000000,0.0326700000000000,0.0321200000000000,0.0327000000000000];

T=493 K时,
y1=[0.0328500000000000,0.0418500000000000,0.0330300000000000,0.0512500000000000,0.0424800000000000,0.0389500000000000,0.0300900000000000,0.0443800000000000];
y2=[0.0381700000000000,0.0415400000000000,0.0292800000000000,0.0273400000000000,0.0295700000000000,0.0197800000000000,0.0216900000000000,0.0180800000000000];

pA = 101*(1 - (2 b + a));
pW = 101*(a+ b);

da/dt=k(4).*k(1).*k(2).*k(3).*pA.*pW./(k(1).*k(2).*k(4).*k(5).*pA^2+k(1).*k(2).*k(3).*pA.*pW+k(4)+k(1).*k(2).*k(4).*pA.*pW+k(1).*k(4).*pW;

db/dt=k(6).*k(1).*k(2).*k(4).*k(5).*pA^2./(k(1).*k(2).*k(4).*k(5).*pA^2+k(1).*k(2).*k(3).*pA.*pW+k(4)+k(1).*k(2).*k(4).*pA.*pW+k(1).*k(4).*pW;

[ 来自科研家族 木虫催化 ]
回复此楼

» 猜你喜欢

» 本主题相关价值贴推荐,对您同样有帮助:

探索真理比占有真理更可贵
已阅   关注TA 给TA发消息 送TA红花 TA的回帖

dingd

铁杆木虫 (职业作家)

【答案】应助回帖


感谢参与,应助指数 +1
csgt0: 金币+1, 谢谢 2013-05-14 15:45:01
1:好好检查下公式,左右括号似乎都不匹配;
2:是要求统一的参数吗(四组数据),如果是哪影响因子T并未在公式里出现。
2楼2013-05-12 14:34:13
已阅   关注TA 给TA发消息 送TA红花 TA的回帖

zhangholmes

至尊木虫 (著名写手)

逍遥门主

引用回帖:
2楼: Originally posted by dingd at 2013-05-12 14:34:13
1:好好检查下公式,左右括号似乎都不匹配;
2:是要求统一的参数吗(四组数据),如果是哪影响因子T并未在公式里出现。

谢谢回复,公式最后忘记加了一个括号。不要求统一参数,每组数据都有一组独立的参数,共四组参数。
公式如下:
da/dt=k(4).*k(1).*k(2).*k(3).*pA.*pW./(k(1).*k(2).*k(4).*k(5).*pA^2+k(1).*k(2).*k(3).*pA.*pW+k(4)+k(1).*k(2).*k(4).*pA.*pW+k(1).*k(4).*pW);

db/dt=k(6).*k(1).*k(2).*k(4).*k(5).*pA^2./(k(1).*k(2).*k(4).*k(5).*pA^2+k(1).*k(2).*k(3).*pA.*pW+k(4)+k(1).*k(2).*k(4).*pA.*pW+k(1).*k(4).*pW);
探索真理比占有真理更可贵
3楼2013-05-12 15:59:36
已阅   关注TA 给TA发消息 送TA红花 TA的回帖
相关版块跳转 我要订阅楼主 zhangholmes 的主题更新
信息提示
请填处理意见