[交流] Project Euler 45 欧拉工程 45 题 已有3人参与

%% Find the next triangle number that is also pentagonal and hexagonal.
% It can be verified that T285 = P165 = H143 = 40755.
% Triangle                   Tn=n(n+1)/2
% Pentagonal                   Pn=n(3n?1)/2
% Hexagonal                   Hn=n(2n?1)
% Elapsed time is 0.095221 seconds.
% ans =
%                 1533776805
function result = euler45()
tic;
n = 1000;
t = (1:n).*((1:n)+1)/2;
p = (1:n).*(3*(1:n)-1)/2;
h = (1:n).*(2*(1:n)-1);
result = max(h(ismember(h,t(ismember(t,p))))); % n<1000时最大的同时是t,p,h的数
while result<40775
    n = n*10;
    t = (1:n).*((1:n)+1)/2;
    p = (1:n).*(3*(1:n)-1)/2;
    h = (1:n).*(2*(1:n)-1);
    result = max(h(ismember(h,t(ismember(t,p)))));
end
toc;
end