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[½»Á÷] ¡¾ÇóÖú¡¿ÇóÖúÓйئ¤S0 £¬¦¤H0£¬¦¤G0 ¼ÆËãÎÊÌ⣿

ÎÒ¿´µ½Ò»¸öÎÄÏ×ÊÇÄÉÃײÄÁÏÎü¸½±½·ÓµÄ£¬×÷Õß²ÉÓÃLangmuirºÍFreundlichÁ½ÖÖÄ£ÐͼÆËãºóÈÏΪ¸üÊÊÓÚFreundlichµÈÎÂÎü¸½£¨R2¸ü½Ó½ü1£©£¬Òò´ËºóµÄ¼ÆË㦤G0£¬¦¤H0ºÍ¦¤S0ʱ£¬×÷Õß˵Generally, the Gibbs free energy ¦¤G0 of adsorption,
enthalpy ¦¤H0 and entropy ¦¤S0 changes was calculated
from data interpolated using the best fitting isotherm. In this study,
the Freundlich isotherm was used to calculate the thermodynamic

parameters using the following equations£º

ln(1/Ce) = (lnKf−¦¤H0) / (RT)                 (1)

¦¤G0 = −nRT                                         (2)

¦¤S0 = (¦¤H0−¦¤G0) / T                           (3)


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A£ºÉÏÃæµÄKfÊDz»ÊǾÍÊÇFreundlichµÈÎÂʽÖеÄKf £¿£¨ÒòΪ×÷Õß˵Îü¸½¸ü·ûºÏFreundlichµÈÎÂÏߣ©

B£ºµÚ¶þ¸öʽ×ÓµÄnÊDz»ÊǾÍÊÇFreundlichµÈÎÂʽÖеÄÖ¸Êýn £¿



Õâ¸öÎÄÕµĵØÖ·£ºhttp://www.sciencedirect.com/sci ... 6723b6eabec1d510d1d


{×÷ÕßÓõÄFreundlichµÈÎÂʽ£º
ln(qe) = lnKf + (1/n)lnCe     }

[ Last edited by weiwei1983 on 2010-2-2 at 15:18 ]
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kxli(½ð±Ò+1):»ý¼«²ÎÓë½»Á÷£¡ 2010-02-03 08:24
µÚ¶þ¸öʽ×ÓÀïµÄnÊÇFreundlichÖеÄn
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2Â¥2010-02-02 15:59:11
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Õâ¸öÖ±ÏßµÄбÂʾ͵ÈÓÚ(lnKf−¦¤H0) / R Â𠣿KfÓÖÊÇÔõôµÃµ½ÄØ£¬ÒòΪ×÷Õß˵Îü¸½¸ü·ûºÏFreundlich£¬
ËùÒÔÏÂÃæÒªÓÃFreundlichÊý¾ÝÇó×ÔÓÉÄÜ£¬ìÊ±ä£¬ìØ±ä£¬
²¢²»ÊÇÓá°Æ½ºâ³£ÊýK for the adsorption was obtained by plotting ln(qe/Ce) vs qe and extrapolating to zero qe.¡± À´ÇóµÄ¡£

[ Last edited by weiwei1983 on 2010-2-2 at 16:15 ]
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weiwei1983(½ð±Ò+1): 2010-02-02 18:13
kxli(½ð±Ò+1):»ý¼«²ÎÓë½»Á÷£¡ 2010-02-03 08:24
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4Â¥2010-02-02 16:16:08
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lnK = ¦¤S0/R − ¦¤H0 / (RT)

ÕâÀïÃæµÄK Êǰ´ÕÕ¡°Æ½ºâ³£ÊýK for the adsorption was obtained by plotting ln(qe/Ce) vs qe and extrapolating to zero qe¡±
»òÕß¡°ln(qe/Ce) vs Ce and extrapolating to zero Ce¡± À´ÇóµÄ¡£ºÃÏñ´ó¶àÔÚLangmuirµÈÎÂÎü¸½ÓÃÕâÖÖ·½·¨ÇóK£¬»¹ÓÐÓÃÏßÐÔÎü¸½½×¶ÎµÄqe/CeÀ´±íʾKµÄ£¬»¹¼ûµ½Ö±½ÓÓÃLangmuir³£ÊýKL´úÌæKµÄ£¬
µ«ÊÇÎÒ×ö¸öÊÔÑé¸ÕºÃ±È½Ï·ûºÏFreundlich£¬ËùÒÔÎÒÒ²Ïë²Î¿¼ÕâÆªÎÄÕÂÉϵÄ×ö·¨À´Ë㣬½á¹û¾ÍÊǸ㲻Çå³þKÔõôË㣬
Çë¸ßÊÖ¶à¶àÖ¸½Ì°¡

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ÎÒÓе㻳ÒÉÄÇÆªÎÄÕÂÀïµÄ ln(1/Ce) = (lnKf−¦¤H0) / (RT)  

ÊDz»ÊÇ´íÁË £¿£¿

ÎÒ¼ûËû²Î¿¼µÄԭʼÎÄÏ×ÀïÊÇÕâÖÖÐÎʽ£º ln(1/C) = lnK−[¦¤H0 / (RT)]

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kxli(½ð±Ò+1):»ý¼«²ÎÓë½»Á÷£¡ 2010-02-03 16:57
Ln(c)=(H/RT)+KºÍÄã¸øµÄÕâ¸öln(1/C) = lnK−[¦¤H0 / (RT)]ÊÇÒ»ÑùµÄ°¡
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7Â¥2010-02-03 10:03:14
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Originally posted by zh1984 at 2010-02-03 10:03:14:
Ln(c)=(H/RT)+KºÍÄã¸øµÄÕâ¸öln(1/C) = lnK−[¦¤H0 / (RT)]ÊÇÒ»ÑùµÄ°¡
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¶Ô£¬ln(1/C) = lnK−[¦¤H0 / (RT)] ¿ÉÒÔ¼ÆËã³öìÊ£¬»¹¿ÉÒԵõ½K£¬²¢ÇÒÕâ¸öʽ×Ó³öÏÖÔÚÆäËûÎÄÕÂÖУ¬
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