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ÊØÍûÕß1412ºÅ(feixiaolin´ú·¢): ½ð±Ò+5 2014-11-03 21:12:07
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3Â¥: Originally posted by ÊØÍûÕß1412ºÅ at 2014-11-03 20:25:38
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KIF17

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ÊØÍûÕß1412ºÅ(feixiaolin´ú·¢): ½ð±Ò+10 2014-11-03 21:11:29
integral (0, 2pi) sqrt(1£«cos2x) dx= 4*sqrt(2) =5.6569
generally,
integral  sqrt(1£«cos2x) dx = sqrt(cos (2x)+1) tan(x) + constant
2Â¥2014-11-03 20:16:23
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ÒýÓûØÌû:
2Â¥: Originally posted by KIF17 at 2014-11-03 20:16:23
integral (0, 2pi) sqrt(1£«cos2x) dx= 4*sqrt(2) =5.6569
generally,
integral  sqrt(1£«cos2x) dx = sqrt(cos (2x)+1) tan(x) + constant

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zjl20111015

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feixiaolin: ½ð±Ò+1 2014-11-03 21:12:23
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zjl20111015

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feixiaolin: ½ð±Ò+5 2014-11-03 21:19:32
ÒýÓûØÌû:
6Â¥: Originally posted by feixiaolin at 2014-11-03 21:09:33
http://www.wolframalpha.com/input/?i=Integrate%5Bsqrt%281%2Bcos%282*x%29%29%2C+%7Bx%2C+0%2C+pi%7D%5D&dataset=

cos(2x)µÄÖÜÆÚΪ£¬×Ô¼º¸Ä³ÉÒ²³É

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Believe in yourself.
7Â¥2014-11-03 21:14:08
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feixiaolin

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ÒýÓûØÌû:
7Â¥: Originally posted by zjl20111015 at 2014-11-03 21:14:08
ÊÇËûÄǸö»ý·Öʽ×ÓÈÃÈËÎó½âÁË£¬»¡³¤Ó¦¸ÃÊǸùºÅÏÂ1+(cosx)^2µÄ»ý·Ö
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Integrate[sqrt(1+cos(x)*cos(x)), {x, 0, 2*pi}]=7.6404
8Â¥2014-11-03 21:19:22
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ÊØÍûÕß1412ºÅ

ľ³æ (СÓÐÃûÆø)

ÒýÓûØÌû:
7Â¥: Originally posted by zjl20111015 at 2014-11-03 21:14:08
ÊÇËûÄǸö»ý·Öʽ×ÓÈÃÈËÎó½âÁË£¬»¡³¤Ó¦¸ÃÊǸùºÅÏÂ1+(cosx)^2µÄ»ý·Ö
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