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rainman0724

Òø³æ (СÓÐÃûÆø)

[ÇóÖú] matlab »æÍ¼ÎÊÌâ ÒÑÓÐ2È˲ÎÓë

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hc=(2.34e-2/f^2)*ln(hc/4)
f=(5.658*x+5.431*(1-x)-5.431)/5.431
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matlab »æÍ¼ÎÊÌâ
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rainman0724

Òø³æ (СÓÐÃûÆø)

ÒýÓûØÌû:
3Â¥: Originally posted by dbb627 at 2014-08-22 17:12:30
>> ezplot('hc-(2.34e-2/f^2)*log(hc/4)')
>> ezplot('hc-(2.34e-2/((5.658*x+5.431*(1-x)-5.431)/5.431)^2)*log(hc/4)')

ллÄãµÄ»Ø¸´£¬ezplotÕâÖÖ·½·¨ÎÒÊÔ¹ýÁË£¬µ«ÊÇÐв»Í¨°¡£¬µÃµ½µÄ½á¹û¸ú²Î¿¼ÎÄÏ׸ø³öµÄ²»Í¬¡£
°´ÕÕÄúµÄÁ½ÖÖ·½·¨£¬·Ö±ð×÷³öµÄͼΪ1ºÍ2.¶øµÚ¶þÖÖ·½·¨×÷µÄͼʲôҲûÓС£
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%syms h f;
%k=solve('h=2.34/100/f^2*log(h/4)')
%ezplot(k)
%axis([0,0.04,0,40])
matlab »æÍ¼ÎÊÌâ-1
1.jpg

4Â¥2014-08-22 20:57:30
ÒÑÔÄ   ¹Ø×¢TA ¸øTA·¢ÏûÏ¢ ËÍTAºì»¨ TAµÄ»ØÌû
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herowolf

ľ³æ (ÕýʽдÊÖ)

¡¾´ð°¸¡¿Ó¦Öú»ØÌû

¡ï ¡ï ¡ï ¡ï
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rainman0724: ½ð±Ò+4, ¡ïÓаïÖú 2014-08-22 21:56:33
ÏÈÇó x¡«f  
for x=1:n
f = ...
end

È»ºó ¶¨Òå
function hcf = myfun(hc, f)

hcf - (2.34e-2/f^2)*ln(hc/4) -hc;


ÔÙÑ­»·
for i = 1£ºn
hc(i) = fsolve(myfun,hc0)
end

×îºó
figure
plot(x,hc)
figure % same figure using hold on
plot (f,hc)

ÏÈÊÔÊÔ¿´°É¡£
2Â¥2014-08-22 16:58:17
ÒÑÔÄ   ¹Ø×¢TA ¸øTA·¢ÏûÏ¢ ËÍTAºì»¨ TAµÄ»ØÌû

dbb627

ÈÙÓþ°æÖ÷ (ÖøÃûдÊÖ)

¡¾´ð°¸¡¿Ó¦Öú»ØÌû

¡ï ¡ï
¸Ðл²ÎÓ룬ӦÖúÖ¸Êý +1
rainman0724: ½ð±Ò+2, ¡ïÓаïÖú 2014-08-22 21:29:53
>> ezplot('hc-(2.34e-2/f^2)*log(hc/4)')
>> ezplot('hc-(2.34e-2/((5.658*x+5.431*(1-x)-5.431)/5.431)^2)*log(hc/4)')
The more you learn, the more you know, the more you know, and the more you forget. The more you forget, the less you know. So why bother to learn.
3Â¥2014-08-22 17:12:30
ÒÑÔÄ   ¹Ø×¢TA ¸øTA·¢ÏûÏ¢ ËÍTAºì»¨ TAµÄ»ØÌû

dbb627

ÈÙÓþ°æÖ÷ (ÖøÃûдÊÖ)

¡¾´ð°¸¡¿Ó¦Öú»ØÌû

¡ï ¡ï
rainman0724: ½ð±Ò+2, ¡ïÓаïÖú 2014-08-22 22:05:50
ezplot('hc-(2.34e-2/f^2)*log(hc/4)',[0 1 -6 6])


matlab »æÍ¼ÎÊÌâ-2
syms h f;
k=solve('h=2.34/100/f^2*log(h/4)','h')
ezplot(k(1))

k =

4.0/exp(1.0*lambertw(0, -(20000*f^2)/117))

matlab »æÍ¼ÎÊÌâ-3
The more you learn, the more you know, the more you know, and the more you forget. The more you forget, the less you know. So why bother to learn.
5Â¥2014-08-22 21:12:40
ÒÑÔÄ   ¹Ø×¢TA ¸øTA·¢ÏûÏ¢ ËÍTAºì»¨ TAµÄ»ØÌû
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