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acmuser

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5Â¥: Originally posted by clausius at 2012-05-17 01:44:04:
µÚÒ»Ì⣺ ÓÉÓÚÊǹãÒå»ý·Ö,ÐèÒª½âÎöÑÓÍØ£¬Òò´Ë²»Äܵ¥´Ó¾­µäÒâÒåÏÂÀí½â,Ô­ÌâÌõ¼þÊÕÁ²,ÐèÒªÖ¸³öºÎÖÖÌõ¼þ(ͨ³£²»Í¬Ìõ¼þϵÄÊÕÁ²,¶ÔÓ¦²»Í¬½á¹û) ÏÂÃæµÄ´ð°¸»ùÓÚ²¼À×¶û¿ÉºÍÐÔ:
P ¿ÉÈ¡Èκθ´Êý£ºP µÄʵ²¿Ð¡ÓÚ¸º1£¬ÇÒP²» ...

that does not make sense to me, if you change variable from z to 1/z, the integral becomes
\int_0^{\infty}z^{2(-p-2)+1}dz, then -p-2<-1, namely p>-1 is also okay? sounds weird.
please let us what is ²¼À×¶û¿ÉºÍÐÔ, or give us the English word for that.
8Â¥2012-05-18 00:31:28
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zijingniao: ½ð±Ò+1, ¡ïÓаïÖú, Äܲ»Äܸø³ö½âÌâ²½Öè°¡ 2012-05-16 18:16:48
СÓêÃÈÃÈ: ½ð±Ò+1, 3Q~ 2012-05-16 19:00:46
1. no such p,
2. ln(2)
2Â¥2012-05-15 21:44:53
ÒÑÔÄ   »Ø¸´´ËÂ¥   ¹Ø×¢TA ¸øTA·¢ÏûÏ¢ ËÍTAºì»¨ TAµÄ»ØÌû

Jackie2011

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zijingniao: ½ð±Ò+2, ¡ï¡ï¡ïºÜÓаïÖú, Äܲ»Äܸø³ö½âÌâ²½Öè°¡ 2012-05-16 18:17:14
СÓêÃÈÃÈ: ½ð±Ò+1, ллӦÖú~ 2012-05-16 19:01:03
µÚÒ»¸ö×ÜÊÇ·¢É¢°¡,ÌâÄ¿´íÁË?
µÚ¶þ¸ö´ð°¸ÊÇln2.
ѧºÃÍâÓ²»ÍüÊýѧ£¡
3Â¥2012-05-15 21:49:15
ÒÑÔÄ   »Ø¸´´ËÂ¥   ¹Ø×¢TA ¸øTA·¢ÏûÏ¢ ËÍTAºì»¨ TAµÄ»ØÌû

clausius

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µÚÒ»Ì⣺ ÓÉÓÚÊǹãÒå»ý·Ö,ÐèÒª½âÎöÑÓÍØ£¬Òò´Ë²»Äܵ¥´Ó¾­µäÒâÒåÏÂÀí½â,Ô­ÌâÌõ¼þÊÕÁ²,ÐèÒªÖ¸³öºÎÖÖÌõ¼þ(ͨ³£²»Í¬Ìõ¼þϵÄÊÕÁ²,¶ÔÓ¦²»Í¬½á¹û) ÏÂÃæµÄ´ð°¸»ùÓÚ²¼À×¶û¿ÉºÍÐÔ:
P ¿ÉÈ¡Èκθ´Êý£ºP µÄʵ²¿Ð¡ÓÚ¸º1£¬ÇÒP²»µÈÓÚ -0.5(k+1), kÊôÓÚÈκÎ×ÔÈ»Êý(1,2,3...)

ÏÖÔÚÄãÖªµÀÕâÑùµÄP´æÔÚ¶øÇҺܶ࣬±ÈÈç -2.6.

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