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yearover银虫 (正式写手)
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[求助]
回复审稿意见，加入了一段矩阵运算的文字描述，求助是否合理
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The proposed A method is an evolutionary algorithm of the B method. This process can be easily described as: the 1st step, get F(0)=K(0)Ψ, according to the Eq. (1) F(x)=K(x)Ψ with x = 0; 根据方程1 F(x)=K(x)Ψ在x = 0时，得到F(0)=K(0)Ψ the 2nd step, matrix translation Ψ = K-1(0)F(0); 矩阵转换得到 Ψ = K-1(0)F(0) the 3rd step, rewrite the Eq. (1) with F(0), F(x) = J(x)F(0) where J(x) = K(x)K-1(0). 用F(0)重新写方程1，得到F(x) = J(x)F(0) It is clear that one can obtain the same results by the A method and B method. The difference between the A method and B method is that J(x) and K(x) must be determined respectively and the A method is directly built by the application of the continuities. 请各位看看，是否符合书写习惯，谢谢 |
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paperhunter
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yearover: 金币+10, ★★★很有帮助 2012-05-16 07:30:52
感谢参与，应助指数 +1
yearover: 金币+10, ★★★很有帮助 2012-05-16 07:30:52
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The proposed A method is an evolutionary algorithm of the B method. This process can be easily described as: The method A is an evolutionary algorithm of method B. the 1st step, get F(0)=K(0)Ψ, according to the Eq. (1) F(x)=K(x)Ψ with x = 0; Step 1, F(0)=K(0)Ψ achieved according to the Eq. (1) F(x)=K(x)Ψ with x = 0; the 2nd step, matrix translation Ψ = K-1(0)F(0); Step 2, Ψ = K-1(0)F(0) get from matrix transformation; the 3rd step, rewrite the Eq. (1) with F(0), F(x) = J(x)F(0) where J(x) = K(x)K-1(0). Step 3, with F(0) introduction, F(x) = J(x)F(0) where J(x) = K(x)K-1(0). It is clear that one can obtain the same results by the A method and B method. The difference between the A method and B method is that J(x) and K(x) must be determined respectively and the A method is directly built by the application of the continuities. It is clear that the same results could be obtained by method A and method B. The difference between the two methods is that J(x) and K(x) must be determined respectively and the method A is directly built by the application of the continuities. |
7楼2012-05-15 21:14:59
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2楼2012-05-15 14:11:35
啸天犬
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3楼2012-05-15 15:59:46
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4楼2012-05-15 16:44:33
