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小木虫论坛-学术科研互动平台 » 学术交流区 » 论文投稿 » 投稿求助 » 回复审稿意见，加入了一段矩阵运算的文字描述，求助是否合理
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yearover

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[求助] 回复审稿意见，加入了一段矩阵运算的文字描述，求助是否合理

The proposed A method is an evolutionary algorithm of the B method. This process can be easily described as:
the 1st step, get F(0)=K(0)Ψ, according to the Eq. (1) F(x)=K(x)Ψ with x = 0; 根据方程1 F(x)=K(x)Ψ在x = 0时，得到F(0)=K(0)Ψ
the 2nd step, matrix translation Ψ = K-1(0)F(0); 矩阵转换得到 Ψ = K-1(0)F(0)
the 3rd step, rewrite the Eq. (1) with F(0), F(x) = J(x)F(0) where J(x) = K(x)K-1(0). 用F(0)重新写方程1，得到F(x) = J(x)F(0)
It is clear that one can obtain the same results by the A method and B method. The difference between the A method and B method is that J(x) and K(x) must be determined respectively and the A method is directly built by the application of the continuities.
请各位看看，是否符合书写习惯，谢谢
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1楼 2012-05-15 13:29:11
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yanwuliaorao

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yearover: 金币+5, ★★★很有帮助 2012-05-15 21:15:35
没看出什么语法或单词错误。楼主好运！
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阳光总在风雨后！
2楼2012-05-15 14:11:35
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啸天犬

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yearover: 金币+5, ★★★很有帮助 2012-05-15 21:15:45
不要说A method和B method，一般应该说method A和method B
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天下兴亡，我的责任！
3楼2012-05-15 15:59:46
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qiqiqiqi

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yearover: 金币+5, ★★★很有帮助 2012-05-15 21:15:53
最好公式的地方另起一行 比较简明
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http://edu.emuch.net/attachment/b0/a6/664055_1294967861_445.gif
4楼2012-05-15 16:44:33
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visitor958

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yearover: 金币+6, ★★★很有帮助, 谢谢~ 2012-05-15 21:16:15
A method 最好写成 Method A
the 1st step 写成 Step 1:....
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5楼2012-05-15 18:59:29
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nono2009

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yearover: 金币+6, ★★★很有帮助 2012-05-16 07:28:47
the 1st step,
the 2nd step,
the 3rd step,
建议改成Step 1，Step 2，Step 3
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6楼2012-05-15 19:32:38
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paperhunter

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yearover: 金币+10, ★★★很有帮助 2012-05-16 07:30:52
The proposed A method is an evolutionary algorithm of the B method. This process can be easily described as:

The method A is an evolutionary algorithm of  method B.

the 1st step, get F(0)=K(0)Ψ, according to the Eq. (1) F(x)=K(x)Ψ with x = 0;

Step 1, F(0)=K(0)Ψ achieved according to the Eq. (1) F(x)=K(x)Ψ with x = 0;

the 2nd step, matrix translation Ψ = K-1(0)F(0);

Step 2, Ψ = K-1(0)F(0) get from matrix transformation;

the 3rd step, rewrite the Eq. (1) with F(0), F(x) = J(x)F(0) where J(x) = K(x)K-1(0).

Step 3, with F(0) introduction, F(x) = J(x)F(0) where J(x) = K(x)K-1(0).

It is clear that one can obtain the same results by the A method and B method. The difference between the A method and B method is that J(x) and K(x) must be determined respectively and the A method is directly built by the application of the continuities.

It is clear that the same results could be obtained by method A  and method B. The difference between the two methods is that J(x) and K(x) must be determined respectively and the method A is directly built by the application of the continuities.
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咱也是有组织的人了...
7楼2012-05-15 21:14:59
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bitwangyang

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yearover: 金币+3, ★★★很有帮助 2012-05-16 07:30:59
像这些解释类的带公式说明的东西要规范化，正式点显得有专业点同等水平的东西中投的概率是要大些的，建议参考一些国外教材上或论文上的描述用语和表达，尽量地道和简洁！祝楼主好运！
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风雨归来路
8楼2012-05-15 21:29:15
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