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【求助】G09荧光光谱例子 运行出错
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用gaussian09计算乙醛分子在乙醇溶液中的荧光光谱。根据手册,一共分成7个步骤,http://www.gaussian.com/g_tech/g_ur/k_scrf.htm 但是计算到第六步出了问题。 输入文件如下: %chk=06-ac # B3LYP/6-31+G(d,p) TD=(Read,NStates=6,Root=1) SCRF=(Solvent=Ethanol,StateSpecific,Read) Geom=Check Guess=Read Acetaldehyde emission state-specific solvation at first excited state optimized geometry 0 1 NonEq=write 出错信息: PCMU: Requested matrix not present on file. Error termination via Lnk1e in /public/g09/l601.exe 请教大家,如何解决这个问题呢? 谢谢! |
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2楼2011-01-24 14:30:26
3楼2011-01-24 16:18:28
4楼2011-01-25 09:24:00
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tandz(金币+1):谢谢参与
zhou2009: 2011-01-26 16:06:12
tandz(金币+1):谢谢参与
zhou2009: 2011-01-26 16:06:12
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请将StateSpecific关键词改为ExternalIteration,这个是Gaussian 09的一个BUG,我专门写信问过Gaussian公司,这个BUG在B01中已经修正,但是在A01和A02中都存在,所以你需要把这个例子中所有的StateSpecific改为ExternalIteration,这两个关键词作用是一样的,在B01中使用这两个关键词的结果是一致的,但是在A01中和A02中使用StateSpecific,即便能得到结果,比如这个例子中计算吸收光谱那一步,其结果也是错的,它仅仅算了真正的StateSpecific中的第一步而已。 Gaussian公司的回复邮件: Thank you for your inquiry. The problem with the example shown in the manual is related to the "StateSpecific" option. Unfortunately, the "StateSpecific" option was connected incorrectly in the current version of G09, but this will be fixed in the next minor revision. As a workaround, you can use the "ExternalIteration" option instead of the "StateSpecific" option (for both the state specific vertical excitation and the emission state specific solvation). The "ExternalIteration" option is a generalization of the "StateSpecific" option. So, please, try the example in the manual again with the only change of removing "StateSpecific" and adding "ExternalIteration" instead. For example, %nproc=16 %mem=2000mb %chk=06-ac # B3LYP/6-31+G(d,p) TD=(Read,NStates=6,Root=1) SCRF=(Solvent=Ethanol,ExternalIteration,Read) Geom=Check Guess=Read Acetaldehyde emission state-specific solvation at first excited state optimized geometry 0 1 NonEq=write |
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7楼2011-01-25 15:01:39
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8楼2011-01-25 15:18:40
11楼2011-01-25 15:35:05
12楼2011-01-25 15:56:57
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您能解释一下那个例子的第6步和第7步吗? 第6步保存non-equilibrium溶剂效应,第7步的B3lyp只是计算能量的,不能像td计算那样给出发射波长,那应该怎样得到发射波长呢? Step 7: Emission to final ground state (part 2). Finally, we compute the ground state energy with non-equibrium solvation, at the excited state geometry and with the static solvation from the excited state. %chk=07-ac # B3LYP/6-31+G(d,p) SCRF=(Solvent=Ethanol,Read) Geom=Check Guess=Read Acetaldehyde: ground state non-equilibrium at excited state geometry. 0 1 NonEq=read |
14楼2011-01-26 14:56:41
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tandz(金币+1):谢谢参与
tandz(金币+1):谢谢参与
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下面是Gaussian公司关于7步计算中的能量的一个计算的说明,包含了你的问题的答案,供参考: Dear Dr. Zhou, As I was saying in my previous email, the "StateSpecific" option in G09 rev. A.02 is connected incorrectly and it is not producing the results that it is supposed to produce, so please do not use the "StateSpecific" option in G09 rev. A.02. For the absorption/emission example in solution, you need to use the "ExternalIteration" option instead, which does produce the correct results. If you follow the whole example given in the manual but correcting the inputs to have "ExternalIteration" instead of "StateSpecific", you should obtain the following results on each one of the 7 proposed jobs in the example: 1) Energy of ground state optimized geometry in solution: SCF Done: E(RB3LYP) = -153.851761719 A.U. after 1 cycles 2) Vertical excitation (absorption) to first excited state from Linear Response calculation in solution (using ground state optimized geometry from job 1): Excited State 1: Singlet-A" 4.3767 eV 283.28 nm f=0.0000 ... Total Energy, E(TD-HF/TD-KS) = -153.690919717 3) Vertical excitation (absorption) to first excited state from a non-equilibrium state-specific calculation (using "ExternalIteration" in solution (using ground state optimized geometry from job 1):SC-PCM: The total energy including the PCM contribution is -153.687679830 a.u. Taking the difference of this energy minus the ground state energy (job 1), the excitation energy is 277.69 nm. 4) Geometry optimization of first excited state in solution (Final energy): Excited State 1: Singlet-A 3.2076 eV 386.53 nm f=0.0014 ... Total Energy, E(TD-HF/TD-KS) = -153.705918841 5) Frequency calculation to confirm that the geometry optimized in job 4 is a stationary point, and a minimum in the potential energy surface of the excited state. 6) Energy of first excited state from a equilibrium state-specific calculation (using "ExternalIteration" in solution (using optimized geometry from job 4):SC-PCM: The total energy including the PCM contribution is -153.707151097 a.u. 7) Energy of ground state from a non-equilibrium calculation in solution (using first excited state optimized geometry from job 4 and its reaction field from job 6): SCF Done: E(RB3LYP) = -153.822029934 A.U. after 10 cycles The difference between these last two energies gives the vertical emission energy, which, in this case, is 396.62 nm. Please, let me know if you have any further questions, |
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zyxme6楼
2011-01-25 11:45
tandz(金币+1):谢谢参与

半熟的小苹果9楼
2011-01-25 15:19
tandz(金币+1):谢谢参与

半熟的小苹果10楼
2011-01-25 15:19
tandz(金币+1):谢谢参与

zyxme13楼
2011-01-25 16:13
tandz(金币+1):谢谢参与

sduqianqia15楼
2011-01-26 15:22
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in solution (using ground state optimized geometry from job 1):