24小时热门版块排行榜    

CyRhmU.jpeg
查看: 6749  |  回复: 6
当前只显示满足指定条件的回帖,点击这里查看本话题的所有回帖

Cabird

新虫 (初入文坛)

[求助] Matlab数值积分结果是虚数

小木虫的各位童鞋们,我现在调试matlab程序遇到一个问题。一个很复杂的关于角度theta的数值积分,我调用自带的quadl函数,结果出现虚数。我后来又根据变步长的simpson算法编了一个数值积分程序,结果还是有虚数,而且我的积分程序和quadl算出的结果还有一些误差。积分函数包含了很多三角函数,还有e的指数函数在里面,但是积分过程中并无傅里叶变换等可以带来虚数的过程,不知道虚数是怎么来的。我把积分函数曲线都画出来了,波动比较大,但是作为一个面积,怎么会出现虚数呢?我把我的八个积分函数表达式以及各自的函数曲线贴出来,希望大神们帮我看看,给点意见。论文卡在这里,一直得不到解决。
%========function group of theta=====================
    function F1=Ff1(theta)
%======== basic formula=============================
% TO identify whether the rotating axis is inside the circle
if rrat<=0
    rm=0.5*(exp((theta-theta0)*tan(phi))-rrat*exp((theta-theta0)*tan(phi)));
     R=0.5*(exp((theta-theta0)*tan(phi))+rrat*exp((theta-theta0)*tan(phi)));
else
    rm=0.5*(exp((theta-theta0)*tan(phi))+rrat*exp(-(theta-theta0)*tan(phi)));
     R=0.5*(exp((theta-theta0)*tan(phi))-rrat*exp(-(theta-theta0)*tan(phi)));
end

a=sin(theta0)/sin(theta)-rm;
F1=2*cos(theta)*(((R^2-a^2)^(1/2))*(0.125*R^2*a-0.25*a^3-0.5*a*rm^2+(R^2-a^2)*rm)...
    +(0.5*pi-asin(a/R))*(0.125*R^4+0.5*rm^2*R^2));
    end

    function F2=Ff2(theta)
%========basic formula=============================
% TO identify whether the rotating axis is inside the circle
if rrat<=0
    rm=0.5*(exp((theta-theta0)*tan(phi))-rrat*exp((theta-theta0)*tan(phi)));
     R=0.5*(exp((theta-theta0)*tan(phi))+rrat*exp((theta-theta0)*tan(phi)));
else
rm=0.5*(exp((theta-theta0)*tan(phi))+rrat*exp(-(theta-theta0)*tan(phi)));
R=0.5*(exp((theta-theta0)*tan(phi))-rrat*exp(-(theta-theta0)*tan(phi)));
end
d=sin(betaS+thetah)/sin(betaS+theta)*exp((thetah-theta0)*tan(phi))-rm;
F2=2*cos(theta)*(((R^2-d^2)^(1/2))*(0.125*R^2*d-0.25*d^3-0.5*d*rm^2+(R^2-d^2)*rm)...
    +(0.5*pi-asin(d/R))*(0.125*R^4+0.5*rm^2*R^2));  
    end

    function G1=Gf1(theta)
%========= basic formula=============================
% TO identify whether the rotating axis is inside the circle
if rrat<=0
    rm=0.5*(exp((theta-theta0)*tan(phi))-rrat*exp((theta-theta0)*tan(phi)));
     R=0.5*(exp((theta-theta0)*tan(phi))+rrat*exp((theta-theta0)*tan(phi)));
else
rm=0.5*(exp((theta-theta0)*tan(phi))+rrat*exp(-(theta-theta0)*tan(phi)));
R=0.5*(exp((theta-theta0)*tan(phi))-rrat*exp(-(theta-theta0)*tan(phi)));
end
a=sin(theta0)/sin(theta)-rm;
G1=(rm^2*(R-a)+rm*(R^2-a^2)+(1/3)*(R^3-a^3))*cos(theta);
    end

    function G2=Gf2(theta)
%=========basic formula=============================
% TO identify whether the rotating axis is inside the circle
if rrat<=0
    rm=0.5*(exp((theta-theta0)*tan(phi))-rrat*exp((theta-theta0)*tan(phi)));
     R=0.5*(exp((theta-theta0)*tan(phi))+rrat*exp((theta-theta0)*tan(phi)));
else
rm=0.5*(exp((theta-theta0)*tan(phi))+rrat*exp(-(theta-theta0)*tan(phi)));
R=0.5*(exp((theta-theta0)*tan(phi))-rrat*exp(-(theta-theta0)*tan(phi)));
end
d=sin(betaS+thetah)/sin(betaS+theta)*exp((thetah-theta0)*tan(phi))-rm;
G2=(rm^2*(R-d)+rm*(R^2-d^2)+(1/3)*(R^3-d^3))*cos(theta);  
    end

    function E1=Ef1(theta)
%=========basic formula=============================
% TO identify whether the rotating axis is inside the circle
if rrat<=0
    rm=0.5*(exp((theta-theta0)*tan(phi))-rrat*exp((theta-theta0)*tan(phi)));
     R=0.5*(exp((theta-theta0)*tan(phi))+rrat*exp((theta-theta0)*tan(phi)));
else
rm=0.5*(exp((theta-theta0)*tan(phi))+rrat*exp(-(theta-theta0)*tan(phi)));
R=0.5*(exp((theta-theta0)*tan(phi))-rrat*exp(-(theta-theta0)*tan(phi)));
end
a=sin(theta0)/sin(theta)-rm;
E1=(cos(theta)/(sin(theta))^3)*(R^2-a^2)^(1/2);  
    end

    function E2=Ef2(theta)
%========= basic formula=============================
% TO identify whether the rotating axis is inside the circle
if rrat<=0
    rm=0.5*(exp((theta-theta0)*tan(phi))-rrat*exp((theta-theta0)*tan(phi)));
     R=0.5*(exp((theta-theta0)*tan(phi))+rrat*exp((theta-theta0)*tan(phi)));
else
rm=0.5*(exp((theta-theta0)*tan(phi))+rrat*exp(-(theta-theta0)*tan(phi)));
R=0.5*(exp((theta-theta0)*tan(phi))-rrat*exp(-(theta-theta0)*tan(phi)));
end
d=sin(betaS+thetah)/sin(betaS+theta)*exp((thetah-theta0)*tan(phi))-rm;
E2=cos(theta+betaS)/((sin(theta+betaS))^3)*(R^2-d^2)^(1/2);
    end

    function H1=Hf1(theta)
%===========basic formula=============================
H1=cos(theta)/(sin(theta))^3;
    end

    function H2=Hf2(theta)
%========= basic formula=============================
H2=cos(theta+betaS)/(sin(theta+betaS))^3;
    end
==========computational parameters==================
d2r=pi/180;
theta0=20*d2r;thetah=100*d2r;rrat=0.6;brat=0.5;
betaS=45*d2r; phi=30*d2r;
A1=sin(betaS+thetah)/sin(theta0)*exp((thetah-theta0)*tan(phi));
B1=cos(betaS);
C1=sin(betaS);
thetaB=acot((A1-B1)/C1);
%===========numerical integration for W and D==============

Wd1=quadl(@Ff1,theta0,thetaB);
Wd2=quadl(@Ff2,thetaB,thetah);
Wd=Wd1+Wd2;

Wp1=quadl(@Gf1,theta0,thetaB);
Wp2=quadl(@Gf2,thetaB,thetah);
Wp=Wp1+Wp2;

Kd1=quadl(@Ef1,theta0,thetaB);
Kd2=quadl(@Ef2,thetaB,thetah);
Dd=-2*cot(phi)*(sin(theta0))^2*Kd1...
    -2*cot(phi)*exp(2*(thetah-theta0)*tan(phi))*(sin(thetah+betaS))^2*Kd2;

Kp1=quadl(@Hf1,theta0,thetaB);
Kp2=quadl(@Hf2,thetaB,thetah);
Dp=-cot(phi)*(sin(theta0))^2*Kp1...
    -cot(phi)*exp(2*(thetah-theta0)*tan(phi))*(sin(thetah+betaS))^2*Kp2;

disp('[Wd1,Wd2,Wp1,Wp2,Kd1,Kd2,Kp1,Kp2]=');
disp([Wd1,Wd2,Wp1,Wp2,Kd1,Kd2,Kp1,Kp2]');

八个被积函数曲线.jpg
回复此楼

» 猜你喜欢

» 本主题相关价值贴推荐,对您同样有帮助:

已阅   回复此楼   关注TA 给TA发消息 送TA红花 TA的回帖

Cabird

新虫 (初入文坛)

引用回帖:
2楼: Originally posted by solar0913 at 2013-03-21 00:09:03
问题出在开根号里,根号下的值为负数,所以导致有虚数。

很多天没上木虫,才看到你的回复。发帖的第二天帮师兄调程序发现根号问题反应过来了,忘记删帖了。
3楼2013-04-08 16:59:41
已阅   回复此楼   关注TA 给TA发消息 送TA红花 TA的回帖
查看全部 7 个回答

solar0913

至尊木虫 (著名写手)

【答案】应助回帖

感谢参与,应助指数 +1
问题出在开根号里,根号下的值为负数,所以导致有虚数。

[ 发自手机版 http://muchong.com/3g ]
2楼2013-03-21 00:09:03
已阅   回复此楼   关注TA 给TA发消息 送TA红花 TA的回帖

gyp0901911

新虫 (初入文坛)

您好!问题解决了吗?我也遇到同样的困难
4楼2013-04-08 17:00:46
已阅   回复此楼   关注TA 给TA发消息 送TA红花 TA的回帖

匿名

用户注销 (正式写手)

本帖仅楼主可见
5楼2013-04-08 23:02:32
已阅   申请EPI   回复此楼   编辑   查看我的主页
信息提示
请填处理意见