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WDD880227(½ð±Ò+1): ¸Ðл½»Á÷Ìáʾ 2012-02-28 15:35:57
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WDD880227(½ð±Ò+1): ¸Ðл½»Á÷Ìáʾ 2012-02-28 15:35:57
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Õâ¸öÊÇÓÉÓÚ»ù×éµÄ²»Õý½»ÐÔµ¼Öµġ£Ñϸñ˵À´£¬Èç¹ûͶӰµÄʱºò²ÉÓÃÒ»¸öÒѾÕý½»µÄ»ù×éÀ´¶¨ÒåµÄ»°£¬¾Í»á±ÜÃâÕâ¸öÎÊÌ⣬µ«ÊÇÄǸöʱºòPDOSµÄÎïÀíÒâÒåûÓÐÏÖÔÚÃ÷È·¡£ËùÒÔÓе㡰ÓãºÍÐÜÕÆ²»¿É¼æµÃ¡±¡£ ¸ü¼ÓÏêϸµÄ½âÊÍ£¬ÎÒÏÂÃæÒýÓÃÈçÏ£º http://www.mail-archive.com/sies ... am.es/msg02951.html ------------------------------------------ Dear Siesta users, I have a problem understanding the output in a .PDOS output file for my system. I am getting negative values in the PDOS for the projection onto a lot of the basis functions. Perhaps my understanding is wrong, but surely this should not be? According to my understanding the PDOS onto a specific basis function should have peaks at the energies corresponding to the eigenfunctions to which it contributes. I restarted the PDOS calculation from the output files of a converged calculation and used 1 SCF iteration with 50x50x50 Monkhorst Pack grid. Regards, Rainer ------------------------------------------- Dear Rainer: When you are working with a non-orthogonal basis set, as is the case in Siesta, neither the PDOS nor the Mulliken population analysis are positive definite magnitudes. The reason is due to the fact that the PDOS is defined as: g_mu(eps) = sum_nu rho_mu,nu S_nu,mu delta(eps-eps_i) rho_mu,nu = sum_i C_mu,i C*_nu,i (i stands for the bands, S stands for the overlap matrix, and C stands for the coefficients of the wave function) and the non-diagonal elements of the density matrix might be negative. However, the term in the diagonal IS positive definite, and it is usually larger than the rest of the terms. Therefore, when the PDOS is negative the value should be small in absolute value. Hope this helps, Javier --------------------------------------- Dear Javier Thanks very much for your reply. This certainly helps me understand why there can be negative values in the PDOS, at least mathematically. But these negative values of PDOS are not physically meaningful, right? So how should I interpret them? Can one just invert them? I am getting negative values that are roughly the same size as the positive values, so I dont feel comfortable just disregarding them. Regards, Rainer ----------------------------------------- Dear Rainer: I do not think you can give any physical meaning to a large negative Projected Density Of States. The problem is rather fundamental. The solution should come from a redefinition of the PDOS as the projection over a basis of orthogonalized orbitals. That would imply a first transformation from our non-orthogonal basis set to a orthogonal one (I guess that you will have to multiply by the inverse of the overlap matrix somewhere). Hope this helps, Javier ================================= |
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