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hlls007

铁虫 (小有名气)

[求助] 关于三角函数的求解问题了(利用基础的三角函数感觉太复杂了!望帮忙!!)

{h*cos(theta 0)+j}的2/3次方+{h*sin(theta 0)的2/3次方}=1
  j取0,0.1,0.2,0.3,0.5时;theta与h的关系。
sin(theta 0)/cos(theta 0)+j=- {tan(theta 0-theta s)的3次方}
   j取0,0.1,0.2,0.3,0.5时;theta 0与theta s的关系!
请帮忙编写c++的程序,希望能给予一定的帮助!谢谢!
?????????
但是他们说是要对方程求解,请问,这样的方程能解么?怎么解?


还有就是0.5*sin{2*(theta-theta0)}+h*sin(theta)+j*sin(theta-theta0)=0怎么求解了?
cos{2*(theta-theta0)}+h*cos(theta)+j*cos(theta-theta0)=0怎么求解?
希望能给予帮助谢谢!

[ Last edited by hlls007 on 2011-7-17 at 10:40 ]
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l刘紫乔

金虫 (正式写手)

用solve
相信自己一定可以!
2楼2011-09-30 22:28:32
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hlls007

铁虫 (小有名气)

能不能说的具体一些
3楼2011-10-01 12:50:43
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474267063

木虫 (著名写手)

St.

★
小雨萌萌(金币+1): 3Q~ 2011-10-12 09:44:24
LZ说的貌似是matlab吧,如果真用C的话,一般都是使用二分法的吧
The fabrication of active optoelectronic devices like micro-disk and their application for laser,amplifier,modulator and biosensor.
4楼2011-10-11 13:22:09
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