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7Â¥: Originally posted by sunjian5773 at 2010-11-30 07:36:25
¼òµ¥Ëµ¾ÍÊÇÏëÓøµÀïÒ¶±ä»»µÄ·½·¨ÍƵ¼³öcos(2m*pi*x/a) ½üËÆµÈÓÚ -2/3*^2£¬ ¼´cos(2m*pi*x/a) ~ -2/3*^2

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2015-08-07 06:10   »Ø¸´  
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11Â¥: Originally posted by feixiaolin at 2015-08-07 06:01:40 ÐÔÖÊ£ºcos(2x)=cos^2(x)-sin^2(x)=1-2sin^2(x) ÓÐ cos(2m*pi*x/a)=1-2*sin^2 cos(2n*pi*y/b)=1-2*^2£¬

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