[交流] 【求助】此程序没有错误，怎么运行不出来？

dimension M(7),omiga(7),Tc(7),Pc(7),Z(7,100000),alpha(7),a(7),b(7)
     *        ,beta(7),q(7),v(7),phi(7),f(7),factor(7)
        real P,r,epsilon,sigma
      parameter(r=83.14,epsilon=1-(2**(0.5)),sigma=1+(2**(0.5)))
        integer i,j
        read(*,*)p1,T
        P=p1/100
        DATA M/16.043,30.070,44.097,58.123,72.150,44.01,28.01/
        DATA omiga/0.012,0.100,0.152,0.2,0.252,0.224,0.048/
        DATA Tc/190.6,305.3,369.8,425.1,469.7,304.2,132.9/
        DATA Pc/45.99,48.72,42.48,37.96,33.70,73.83,34.99/
        do 1 i=1,7
            alpha(i)=(1+(0.37464+1.54226*omiga(i)-0.26992*(omiga(i)**2)*
     *        (1-(T/Tc(i)))**(0.5)))**2
1     continue
      do 2 i=1,7
           a(i)=0.45724*(R**2)*(Tc(i)**2)/Pc(i)*alpha(i)
2     continue
      do 3 i=1,7
           b(i)=0.07779*R*Tc(i)/Pc(i)
3     continue
      do 4 i=1,7
           beta(i)=b(i)*P/(R*T)
4     continue
      do 5 i=1,7
           q(i)=a(i)/(b(i)*R*T)
5     continue
        j=0
      do 6 i=1,7
7           Z(i,(j+1))=1+beta(i)-q(i)*beta(i)*(Z(i,j)-beta(i))/(Z(i,j)+
     *        epsilon*beta(i))*(Z(i,j)+sigma*beta(i))
          do 8 j=1,100000
           factor(i)=(factor(i)-Z(i,j)/Z(i,(j+1)))
8     continue
      if(ABS(Z(i,(j+1))-Z(i,j)).lt.1E-6)goto 7
6     continue
         do 9 i=1,7
        v(i)=(1/(sigma-epsilon))*log((factor(i)+sigma*beta(i))/(factor(i)+
     *epsilon*beta(i)))
9     continue
        do 10 i=1,7
        phi(i)=exp(factor(i)-1-log(factor(i)-beta(i))-q(i)*v(i))
        f(i)=phi(i)*P1
10    continue
      write(*,*)f(i),phi(i)
        end

Originally posted by zyj8119 at 2010-11-24 23:49:15:

我就是想用Z的新数值减去Z的旧数值，然后只要这个差值达到收敛标准，就使得循环跳出，其中100000是一个约数，我觉得循环这么多步，应该收敛了，但是假如还没有收敛，怎么办？

Originally posted by ykwang at 2010-11-24 22:33:36:
这一段代码是错误的
     do 6 i=1,7
7           Z(i,(j+1))=1+beta(i)-q(i)*beta(i)*(Z(i,j)-beta(i))/(Z(i,j)+
     *        epsilon*beta(i))*(Z( ...