2楼: Originally posted by bcsnow at 2016-11-03 11:42:15
-元=次方程，可以直接求解

3楼: Originally posted by 柠檬西柚 at 2016-11-03 11:52:27
额。。我式子好像没写清楚，是（t/t1）的n次方，然后再乘t
...

4楼: Originally posted by bcsnow at 2016-11-03 13:05:37
syms t
n=10
t1=10
t2=350
equ=t+t*(t/t1)^n-n*t2
solve(equ,t)...

6楼: Originally posted by pdl9527 at 2016-11-04 18:45:27
function question_4
clear;clc
x0=5;
t=fzero(@fun,x0)
function y=fun(t)
t1=10;
t2=350;
n=10;
y=t+t*(t/t1)^n-n*t2;