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北京石油化工学院2026年研究生招生接收调剂公告
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hanmei98232

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[求助] 求助 我自己仿照其他帖子写了个分段函数非线性拟合的程序一直出错 求高手! 已有1人参与

clear
tic
fun1=inline('-((beta(1)*x)/(beta(2)*x+1)).*8.314*298.15*(log(x)-0.784*(1.7321*x.^0.5/(1+2.0785*x.^0.5)+1.6667*log(1+2.0785*x.^0.5))+2.6667*x.*(beta(3)+beta(4)*(1+(-1-3.464*x.^0.5+6*x).*exp(-3.464*x.^0.5))/(12*x))+2.8289*x.^2*beta(5))+0.07214','beta','x');
fun2=inline('((beta(1)*x)/(beta(2)*x+1)).*8.314*298.15*(log(x)-0.784*(1.7321*x.^0.5/(1+2.0785*x.^0.5)+1.6667*log(1+2.0785*x.^0.5))+2.6667*x.*(beta(3)+beta(4)*(1+(-1-3.464*x.^0.5+6*x).*exp(-3.464*x.^0.5))/(12*x))+2.8289*x.^2*beta(5))+0.07214','beta','x');
fun=@(beta,x)((x<1).*fun1(beta,x)+(x>=1).*fun2(beta,x));
x=[0.19727        0.39798        0.60182        0.8034        0.98454        1.78733        2.05406        2.51801        3.16362        3.69954        4.5584 ];
y=[0.07282919        0.07366338        0.07454467        0.07522262        0.07593838        0.07919294        0.08033517        0.08203459        0.08494242        0.0867815        0.09083547];
beta=nlinfit(x,y,fun,[0.1,0.2,0.1,0.1,0]);
m=beta(1);
n=beta(2);
a=beta(3);
b=beta(4);
c=beta(5);
warning off all
y1=-((beta(1)*x)/(beta(2)*x+1)).*8.314*298.15*(log(x)-0.784*(1.7321*x.^0.5/(1+2.0785*x.^0.5)+1.6667*log(1+2.0785*x.^0.5))+2.6667*x.*(beta(3)+beta(4)*(1+(-1-3.464*x.^0.5+6*x).*exp(-3.464*x.^0.5))/(12*x))+2.8289*x.^2*beta(5))+0.07214;
y2=((beta(1)*x)/(beta(2)*x+1)).*8.314*298.15*(log(x)-0.784*(1.7321*x.^0.5/(1+2.0785*x.^0.5)+1.6667*log(1+2.0785*x.^0.5))+2.6667*x.*(beta(3)+beta(4)*(1+(-1-3.464*x.^0.5+6*x).*exp(-3.464*x.^0.5))/(12*x))+2.8289*x.^2*beta(5))+0.07214;
yfit(1:5)=y1;
yfit(6:11)=y2;
plot(x,y,'*')
hold on;
plot(x,yfit,'r-')
toc
求助 我自己仿照其他帖子写了个分段函数非线性拟合的程序一直出错 求高手!新手 刚刚接触 非常感谢
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dbb627

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【答案】应助回帖

感谢参与,应助指数 +1
CODE:
fun1=inline('-((beta(1)*x)/(beta(2)*x+1)).*8.314*298.15*(log(x)-0.784*(1.7321*x.^0.5/(1+2.0785*x.^0.5)+1.6667*log(1+2.0785*x.^0.5))+2.6667*x.*(beta(3)+beta(4)*(1+(-1-3.464*x.^0.5+6*x).*exp(-3.464*x.^0.5))/(12*x))+2.8289*x.^2*beta(5))+0.07214','beta','x');
fun2=inline('((beta(1)*x)/(beta(2)*x+1)).*8.314*298.15*(log(x)-0.784*(1.7321*x.^0.5/(1+2.0785*x.^0.5)+1.6667*log(1+2.0785*x.^0.5))+2.6667*x.*(beta(3)+beta(4)*(1+(-1-3.464*x.^0.5+6*x).*exp(-3.464*x.^0.5))/(12*x))+2.8289*x.^2*beta(5))+0.07214','beta','x');
fun=@(beta,x)((x<1).*fun1(beta,x)+(x>=1).*fun2(beta,x));
x=[0.19727        0.39798        0.60182        0.8034        0.98454        1.78733        2.05406        2.51801        3.16362        3.69954        4.5584 ];
y=[0.07282919        0.07366338        0.07454467        0.07522262        0.07593838        0.07919294        0.08033517        0.08203459        0.08494242        0.0867815        0.09083547];
beta=nlinfit(x,y,fun,[0.1,0.2,0.1,0.1,0]);
plot(x,y,'ro',x,fun(beta,x),'k.')

The more you learn, the more you know, the more you know, and the more you forget. The more you forget, the less you know. So why bother to learn.
2楼2014-03-19 14:56:37
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