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lilihurry

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2Â¥: Originally posted by feixiaolin at 2013-11-18 21:28:58
tanB+tanA=2*tanB  (ԭʽ)
(tanB-tanA)^2=4*(tanB)^2-4*tanB*tanA=4*tanB*( tanB-tanA)
tanB-tanA=4*tanB
tan(B-A)= (tanB-tanA)/(1+ tanB*tanA)= 4*tanB/(1+ tanB*tanA)
ԭʽÁ½²àͬ³ËtanB£¬ÓÐtanB*tanA=(tanB) ...

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3Â¥2013-11-18 22:10:58
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feixiaolin

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lilihurry: ½ð±Ò+5 2013-11-19 09:21:41
tanB+tanA=2*tanB  (ԭʽ)
(tanB-tanA)^2=4*(tanB)^2-4*tanB*tanA=4*tanB*( tanB-tanA)
tanB-tanA=4*tanB
tan(B-A)= (tanB-tanA)/(1+ tanB*tanA)= 4*tanB/(1+ tanB*tanA)
ԭʽÁ½²àͬ³ËtanB£¬ÓÐtanB*tanA=(tanB)^2£»´úÈëÉÏʽ
tan(B-A)= 4*tanB/(1+ (tanB)^2)£¬ÕûÀí=2*sinB
2Â¥2013-11-18 21:28:58
ÒÑÔÄ   »Ø¸´´ËÂ¥   ¹Ø×¢TA ¸øTA·¢ÏûÏ¢ ËÍTAºì»¨ TAµÄ»ØÌû

feixiaolin

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ÒýÓûØÌû:
3Â¥: Originally posted by lilihurry at 2013-11-18 22:10:58
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4Â¥2013-11-18 22:36:17
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lilihurry

Òø³æ (СÓÐÃûÆø)

ÒýÓûØÌû:
4Â¥: Originally posted by feixiaolin at 2013-11-18 22:36:17
¸ù¾Ýtan¦Á+tan¦Â=2tan2¦Â, ÓÃtan¦Â±íʾtan¦Á£¬
´úÈëtan(¦Á-¦Â)µÄ±í´ïʽ¡£...

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