4楼: Originally posted by nandehutu9327 at 2013-01-27 11:03:58
令(x+35)^1/3=a, (26-x)^1/3=b, 则有a+b=1, 又a^3+b^3=61=(a+b)(a^2-ab+b^2)
所以a^2-ab+b^2=61，ab=-20, 解得a=5,b=-4或a=-4,b=5, 从而算得x=125或x=-99