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amorphous

铁杆木虫 (著名写手)

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[求助] matlab解非线性方程组,求助!

帮忙看一下下列程序,如何求得实数解.

function q=zxxfun(n)
logkp=[11.3,6.2,14.8,12.4,19.5,17.1,22.5,2.4,9.8];                                                                        
p=1;
p0=1;
nn10=1;
nn20=2;
q(1)=logkp(1)-(log10(n(4))+log10(n(5))+2*log10(sum(n))-3*log10(n(2))-log10(n(1))-2*log10(p/p0));
q(2)=logkp(2)-(2*log10(n(4))+log10(n(6))+3*log10(sum(n))-4*log10(n(2))-2*log10(n(1))-3*log10(p/p0));
q(3)=logkp(3)-(2*log10(n(4))+log10(n(7))+4*log10(sum(n))-5*log10(n(2))-2*log10(n(1))-4*log10(p/p0));
q(4)=logkp(4)-(3*log10(n(4))+log10(n(8))+5*log10(sum(n))-6*log10(n(2))-3*log10(n(1))-5*log10(p/p0));
q(5)=logkp(5)-(3*log10(n(4))+log10(n(9))+6*log10(sum(n))-7*log10(n(2))-3*log10(n(1))-6*log10(p/p0));
q(6)=logkp(6)-(4*log10(n(4))+log10(n(10))+7*log10(sum(n))-8*log10(n(2))-4*log10(n(1))-7*log10(p/p0));
q(7)=logkp(7)-(4*log10(n(4))+log10(n(11))+8*log10(sum(n))-9*log10(n(2))-4*log10(n(1))-8*log10(p/p0));
q(8)=logkp(8)-(log10(n(2))+log10(n(3))-log10(n(1))-log10(n(4)));
q(9)=logkp(9)-(log10(n(3))+log10(sum(n))-2*log10(n(1))-log10(p/p0));
q(10)=nn10-(n(1)+2*n(3)+n(4));
q(11)=2*nn20-(2*n(2)+2*n(4)+4*n(5)+4*n(6)+6*n(7)+6*n(8)+8*n(9)+8*n(10)+10*n(11));

clear

options=optimset('Display','iter');
n=fsolve(@zxxfun,[0.5 0.5 0.1 0.1 0.1 0.1 0.1 0.1 0.1 0.1,0.1],options);
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dingd

铁杆木虫 (职业作家)

【答案】应助回帖

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感谢参与,应助指数 +1
amorphous: 金币+100, ★★★★★最佳答案, 谢谢。 2012-05-25 15:16:06
不知道理解对否,用1stOpt计算:
CODE:
Constant logkp=[11.3,6.2,14.8,12.4,19.5,17.1,22.5,2.4,9.8];
Constant p=1,p0=1,nn10=1,nn20=2;
ConstStr f=sum(i=1:11)(n[i]);
Function logkp[1]-(log(n4)+log(n5)+2*log(f)-3*log(n2)-log(n1)-2*log(p/p0));
         logkp[2]-(2*log(n4)+log(n6)+3*log(f)-4*log(n2)-2*log(n1)-3*log(p/p0));
         logkp[3]-(2*log(n4)+log(n7)+4*log(f)-5*log(n2)-2*log(n1)-4*log(p/p0));
         logkp[4]-(3*log(n4)+log(n8)+5*log(f)-6*log(n2)-3*log(n1)-5*log(p/p0));
         logkp[5]-(3*log(n4)+log(n9)+6*log(f)-7*log(n2)-3*log(n1)-6*log(p/p0));
         logkp[6]-(4*log(n4)+log(n10)+7*log(f)-8*log(n2)-4*log(n1)-7*log(p/p0));
         logkp[7]-(4*log(n4)+log(n11)+8*log(f)-9*log(n2)-4*log(n1)-8*log(p/p0));
         logkp[8]-(log(n2)+log(n3)-log(n1)-log(n4));
         logkp[9]-(log(n3)+log(f)-2*log(n1)-log(p/p0));
         nn10-(n1+2*n3+n4);
         2*nn20-(2*n2+2*n4+4*n5+4*n6+6*n7+6*n8+8*n9+8*n10+10*n11);

n4: 0.818320026230474
n5: 0.585572164827173
n1: 4.65521821183815E-6
n2: 0.0105340963919806
n3: 0.0908376592736609
n6: 1.85174177533351E-13
n7: 5.15897663173426E-7
n8: 8.17642694378187E-17
n9: 7.20355202419344E-12
n10: 1.14168605646827E-21
n11: 2.00691894813261E-18
2楼2012-05-25 10:27:19
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csgt0

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【答案】应助回帖

感谢参与,应助指数 +1
楼上正解,在matlab里找初值很困难
showmethemoney
3楼2012-05-25 10:58:22
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