6楼: Originally posted by yahoohoo at 2011-09-05 17:31:51:
在使用很多bins的条件下，图1应该是图2归一化的结果。
完整的计算均方末端矩的公式是 \langle R_e^2 \rangle = {\int P(R_e) R_e^2 d R_e} \over {\int P(R_e) R_e^2 d R_e}。不明白为什么你用两个图计算的结果 ...

1楼: Originally posted by jolly1987 at 2011-09-05 14:40:55:
请问在DPD中如何计算获得均方末端距？在Analysis里有看到End-to-end distribution,帮助软件说：“End-point distribution: returns a histogram of the end-to-end distance of a molecule for each of the frame ...

2楼: Originally posted by yahoohoo at 2011-09-05 16:06:11:
这段话的意思是：先建立末端矩的分布，也就是P(R_e)。那么均方末端矩$\sqrt \langle R_e^2 \rangle = \int P(R_e) R_e^2 d R_e$。

3楼: Originally posted by jolly1987 at 2011-09-05 16:21:39:
不好意思，请问“$\sqrt \langle R_e^2 \rangle = \int P(R_e) R_e^2 d R_e$“是什么？
请问图中Distribution的单位是什么？Bin Count是什么？单位是什么？谢谢！