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[ Last edited by zh09 on 2011-6-26 at 23:32 ]
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ben_ladeng(½ð±Ò+1): лл²ÎÓëÌÖÂÛ 2011-06-28 00:23:08
mathematica´úÂëIntegrate[1/(1 - x^3/2)^(1/3), {x, 0, 2^(1/3)}]
½á¹û(2 2^(1/3) \[Pi])/(3 Sqrt[3])
2Â¥2011-06-27 14:32:47
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Originally posted by xiaoqing8569 at 2011-06-27 14:32:47:
mathematica´úÂëIntegrate[1/(1 - x^3/2)^(1/3), {x, 0, 2^(1/3)}]
½á¹û(2 2^(1/3) \[Pi])/(3 Sqrt[3])

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3Â¥2011-06-28 12:28:11
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sunyang1988(½ð±Ò+1): лл½»Á÷ 2011-06-30 16:01:32
quad('1./(1-x.^3/2).^(1/3)',0,2^(1/3))

ans =

    1.5235
The more you learn, the more you know, the more you know, and the more you forget. The more you forget, the less you know. So why bother to learn.
4Â¥2011-06-29 09:30:33
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sunyang1988(½ð±Ò+2): лл½»Á÷ 2011-07-08 16:56:31
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5Â¥2011-07-04 01:55:01
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sunyang1988(½ð±Ò+1): лл½»Á÷ 2011-07-21 00:14:56
x*hypergeom([1/3, 1/3],[4/3],1/2*x^3)
6Â¥2011-07-16 20:40:39
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