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dubo

½ð³æ (ÖøÃûдÊÖ)

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ÓàÔó³É(½ð±Ò+2): ¹ÄÀø½»Á÷£¡ 2011-06-04 19:32:39
ÒýÓûØÌû:
Originally posted by wangww2011 at 2011-06-03 13:22:19:
½á¹û
CODE:
31626
elapsed time=0.020000 seconds.

c´úÂë
[code]
#include <stdio.h>
#include <math.h>
#include <time.h>

#define TIMERSTART clock_t start_time,stop ...

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#include

#define TIMERSTART clock_t start_time,stop_time;double elapsed_time;start_time = clock();
#define TIMERSTOP stop_time = clock();elapsed_time=(double)(stop_time-start_time)/CLOCKS_PER_SEC;printf("elapsed time=%f seconds.\n",elapsed_time);
9Â¥2011-06-04 14:56:22
ÒÑÔÄ   »Ø¸´´ËÂ¥   ¹Ø×¢TA ¸øTA·¢ÏûÏ¢ ËÍTAºì»¨ TAµÄ»ØÌû
²é¿´È«²¿ 15 ¸ö»Ø´ð

huycwork

½ð³æ (ÖøÃûдÊÖ)

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dubo(½ð±Ò+1): ¶àл½»Á÷ 2011-06-04 14:42:08
ÓàÔó³É(½ð±Ò+2, ³ÌÐòÇ¿Ìû+1): ¹ÄÀø½»Á÷£¡ 2011-06-04 19:31:23
C++´úÂ룺
CODE:
#include
enum {BUFSZ = 10000};

size_t eular21(){
        size_t buf[BUFSZ];
        memset(buf, 0, sizeof buf);
        for(size_t i = 1; i < BUFSZ; ++i){
                for(size_t j = i+i; j < BUFSZ; j+=i){
                        buf[j] += i;
                }
        }
        size_t d, s = 0;
        for(size_t i = 2; i < BUFSZ; ++i){
                d = buf[i];
                if(i == buf[d]){
                        if(i != d)
                                s += i;
                }
        }
        return s;
}

int main(){
        std::cout< }

äöÎеÄÖÐÐÄÓÐÒ»¿é¿ÕµØ£¬¿Õ¿ÕµÄ¡£
2Â¥2011-06-02 22:34:29
ÒÑÔÄ   »Ø¸´´ËÂ¥   ¹Ø×¢TA ¸øTA·¢ÏûÏ¢ ËÍTAºì»¨ TAµÄ»ØÌû

wangww2011

ľ³æ (ÖøÃûдÊÖ)

¡ï ¡ï ¡ï ¡ï
Сľ³æ(½ð±Ò+0.5):¸ø¸öºì°ü£¬Ð»Ð»»ØÌû
dubo(½ð±Ò+1): ¶àл½»Á÷ 2011-06-04 14:43:26
ÓàÔó³É(½ð±Ò+2): ¹ÄÀø½»Á÷£¡ 2011-06-04 19:31:33
½á¹û
CODE:
31626
elapsed time=0.020000 seconds.

c´úÂë
CODE:
#include
#include
#include

#define TIMERSTART clock_t start_time,stop_time;double elapsed_time;start_time = clock();
#define TIMERSTOP stop_time = clock();elapsed_time=(double)(stop_time-start_time)/CLOCKS_PER_SEC;printf("elapsed time=%f seconds.\n",elapsed_time);


int sumdivisors(int n){
  int i,sum=1,sqrtn=sqrt(n);
  for(i=2;i     if(n%i==0)sum+=i+n/i;
  }
  if(sqrtn*sqrtn==n)sum-=sqrtn;
  return sum;
}

int euler21(int n){
  int i,sum=0,tmp;
  for(i=3;i     tmp=sumdivisors(i);
    if(tmp!=i&&tmp       sum+=i;
    }
  }
  
  return sum;
}


int main(void){
int i;

TIMERSTART;

printf("%d\n",euler21(10000));
  
TIMERSTOP;

  return 0;
}

3Â¥2011-06-03 13:22:19
ÒÑÔÄ   »Ø¸´´ËÂ¥   ¹Ø×¢TA ¸øTA·¢ÏûÏ¢ ËÍTAºì»¨ TAµÄ»ØÌû

libralibra

ÖÁ×ðľ³æ (ÖøÃûдÊÖ)

æôÆï½«¾ü

¡ï ¡ï ¡ï ¡ï
Сľ³æ(½ð±Ò+0.5):¸ø¸öºì°ü£¬Ð»Ð»»ØÌû
dubo(½ð±Ò+1): ¶àл½»Á÷ 2011-06-04 14:43:53
ÓàÔó³É(½ð±Ò+2, ³ÌÐòÇ¿Ìû+1): ¹ÄÀø½»Á÷£¡ 2011-06-04 19:31:45
¿´±¿×¾µÄmatlab°É
CODE:
function result = euler21()
tic;
result = [];
for i=1:10000
    if d(i)~=i && d(d(i))==i
        result = [result,i];
    end
end
result = sum(unique(result));
toc;
end

%% Let d(n) denote the sum of proper divisors of n (numbers less than n which divide evenly into n).
% For example, the proper divisors of 220 are 1, 2, 4, 5, 10, 11, 20, 22, 44, 55 and 110; therefore d(220) = 284.
% sub function to compute d(n), called by 21 and 23
function s = d(n)
s = 0;
for i=1:n-1
    if mod(n,i)==0
        s = s+i;
    end
end
end

matlab/VB/python/c++/Javaд³ÌÐòÇë·¢QQÓʼþ:790404545@qq.com
4Â¥2011-06-03 16:36:21
ÒÑÔÄ   »Ø¸´´ËÂ¥   ¹Ø×¢TA ¸øTA·¢ÏûÏ¢ ËÍTAºì»¨ TAµÄ»ØÌû
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