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holmescn

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The sum of the squares of the first ten natural numbers is,
1^2 + 2^2 + ... + 10^2 = 385
The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)^2 = 55^2 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025-385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

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1^2 + 2^2 + ... + 10^2 = 385
ËüÃÇµÄºÍµÄÆ½·½Îª£º
(1 + 2 + ... + 10)^2 = 55^2 = 3025
ËùÒÔ£¬Ç°10¸ö×ÔÈ»ÊýµÄƽ·½ºÍÓëºÍµÄƽ·½²î3025-385=2640

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25502500-338350=25164150
2Â¥2011-05-13 12:24:17
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libralibra

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matlab¸ã¾ØÕóÔËËãµÄÈ·¿ì
CODE:
%% Find the difference between the sum of the squares of 1:100 and the square of the sum.
function result = euler6()
tic;
result = sum(1:100).^2-sum((1:100).^2);
toc;
end

½á¹û
CODE:
% Elapsed time is 0.000032 seconds.
% ans =
%     25164150

matlab/VB/python/c++/Javaд³ÌÐòÇë·¢QQÓʼþ:790404545@qq.com
3Â¥2011-05-13 14:24:17
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huycwork

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ÓàÔó³É(½ð±Ò+2): ¹ÄÀøÌÖÂÛ£¡ 2011-05-13 21:17:42
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CODE:
#define        SUM(start, end) ((start + end) * end / start / 2)
int main (int argc, char *argv[]){
        printf ("sum is: %d\n", SUM(5, 995) + SUM(3, 999) - SUM(15, 990));
        return 0;
}

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4Â¥2011-05-13 17:07:26
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huycwork

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m*(m+1)*((2*m + 1)/3 - 1)/2
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5Â¥2011-05-13 22:32:35
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holmescn

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