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ldoop

Ìú¸Ëľ³æ (ÖøÃûдÊÖ)


[½»Á÷] ¡¾ÇóÖú¡¿rsolveÎÊÌâ

Hi all,

I want to calculate the expression by a recurrence equation but I got this error:
RSolve::litarg: To avoid possible ambiguity, the arguments of the dependent variable in Hypergeometric2F1[a,a,a+n,z] should literally match the independent variables. >>

the code is:
F[n_] := Hypergeometric2F1[a, a, a + n, z]
RSolve[{(n + a) (n + a - 1 - (2 n - 1) z) F[n] - (n + a) (n + a - 1) (1 - z) F[n - 1] + n^2 F[n + 1] == 0,
  F[0] == ((a - 1) (1 - z))/(a - 1 + z) Hypergeometric2F1[a, a, a - 1, z]}, F[n],n]

Çë´ó¼Ò°ïæ¿´¿´ ³ÌÐòÓÐɶÎÊÌâ »òÕßÓиüºÃµÄ°ì·¨Çó³öF[n],ллÁË
»Ø¸´´ËÂ¥
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mshwangg

ÖÁ×ðľ³æ (ÕýʽдÊÖ)

¡ï ¡ï
ÓàÔó³É(½ð±Ò+2):ÐÁ¿àÁË£¡ 2010-10-19 15:10:59
ldoop(½ð±Ò+1): 2010-10-21 20:02:57
ldoop(½ð±Ò+1): 2010-10-21 20:03:08
ÒýÓûØÌû:
Originally posted by ldoop at 2010-10-18 16:38:26:



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4Â¥2010-10-19 13:57:24
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²é¿´È«²¿ 12 ¸ö»Ø´ð

mshwangg

ÖÁ×ðľ³æ (ÕýʽдÊÖ)

¡ï ¡ï
ldoop(½ð±Ò+1):лл²ÎÓë
ÓàÔó³É(½ð±Ò+1):лл²ÎÓëÓ¦Öú£¡ 2010-10-16 17:08:34
ldoop(½ð±Ò+1): 2010-10-18 16:39:03
ldoop(½ð±Ò+1): 2010-10-21 22:31:22
µÚ¶þ¸ö·½³ÌÊÇÏÔÈ»µÄ½á¹û£¬¿ÉÒÔ´ÓF[n]¶¨ÒåÖ±½ÓµÃ³ö£¬¶ø²¢·ÇÊdzõÖµ¡£Òò´ËÄ㻹ÐèÒªÁíÍâÒ»¸ö·½³Ì²ÅÄܽâ³öÀ´
2Â¥2010-10-16 14:12:38
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ldoop

Ìú¸Ëľ³æ (ÖøÃûдÊÖ)


ajian04:лл²ÎÓë½»Á÷~ 2010-10-22 16:16:18
ÒýÓûØÌû:
Originally posted by ldoop at 2010-10-15 16:16:41:
Hi all,

I want to calculate the expression by a recurrence equation but I got this error:
RSolve::litarg: To avoid possible ambiguity, the arguments of the dependent variable in Hypergeometric2 ...

ÎÒ¸ø¶¨F[0]Ϊ³£Êý£¬ÈÔÈ»Çó²»³öÀ´£¬ÇëÎÊÓ¦¸ÃÈçºÎ´¦Àí£¿Ð»Ð»
3Â¥2010-10-18 16:38:26
ÒÑÔÄ   »Ø¸´´ËÂ¥   ¹Ø×¢TA ¸øTA·¢ÏûÏ¢ ËÍTAºì»¨ TAµÄ»ØÌû

ldoop

Ìú¸Ëľ³æ (ÖøÃûдÊÖ)


¡ï ¡ï
ajian04(½ð±Ò+2):лл²ÎÓë½»Á÷~ 2010-10-22 16:16:30
ÒýÓûØÌû:
Originally posted by mshwangg at 2010-10-19 13:57:24:

ÏȰïÎÒ½âÊÍһϣ¬¼ÈÈ»ÄãÒѾ­¶¨ÒåF[n_]ÁË£¬ÎªºÎ»¹ÒªÇóF[n]£¿
¼Ù¶¨F[n]µÄ¶¨ÒåºÍµÚÒ»¸ö·½³ÌÊÇ×ÔÇ¢µÄ£¬ÄÇôµÚÒ»¸ö·½³Ì¾ÍÊÇÏÔÈ»µÄÁË¡£
Èç¹û²»ÖªµÀF[n]µÄ¶¨Ò壬ͨ¹ýµÚÒ»¸öºÍµÚ¶þ¸ö·½³Ìµ¹ÊÇ¿ÉÒÔÇó³öÀ´F[n]µÄ±í´ïʽ£¨ ...

ºÃ°É£¬ÎÒ¿ÉÒÔÈ¥µô¶¨Ò壬ȻºóÇóµÄ F[n]£º
DifferenceRoot[ Function[{y, n]}, {(n +a) (1 + n + a) (-1 +  z) y[n] + (1 + n + a) (n + a - z - 2 n z) y[1 + n] + (1 + n)^2 y[ 2 + n] == 0, y[0] == (1 - z)^-a, y[1]== Hypergeometric2F1[a, a, a + 1, z]}]][n]
²»ÖªµÀÊÇ·ñÕýÈ·£¿
µ«ÊÇÎÒÔÚ½øÐÐNMaximize¼ÆËãʱ£¬»¹ÊÇÓÐÎÊÌ⣬Çë°ïæ¿´¿´ÎҵijÌÐò£º

n = Table[{5, 4, 4, 4, 3, 3, 2, 2, 2, 1, 1, 1, 1, 1, 1, 1, 1}];
f[r_, x_, a_, m_] :=
DifferenceRoot[ Function[{y,m]}, {(m +a) (1 + m + a) (-1 +  z) y[m] + (1 + m + a) (m + a - z - 2 m z) y[1 + m] + (1 + m)^2 y[ 2 + m] == 0, y[0] == (1 - z)^-a, y[1]== Hypergeometric2F1[a, a, a + 1, z]}]][m]
    L[r_, x_, a_] :=
   Sum[n[[j]] (Log[r] + Log[x]) + LogGamma[a + 1] +
     LogGamma[n[[j]]] - (n - a) Log[1 - x + r x] +
     Log[f[r, x, a, n[[j]]]] - Log[x] - Log[n[[j]]] -  LogGamma[n[[j]] + a] -
     Log[HypergeometricPFQ[{1, 1, 1}, {2, 1 + a}, x] - (1 - r) HypergeometricPFQ[{1, 1, 1}, {2, 1 + a},  x - r x]], {j, 1, Length[n]}];
NMaximize[{N[L[r, x, a]], 0 < x, x < 1, 0 < r, r < 1, a > 0}, {x, r, a}]

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5Â¥2010-10-21 22:02:59
ÒÑÔÄ   »Ø¸´´ËÂ¥   ¹Ø×¢TA ¸øTA·¢ÏûÏ¢ ËÍTAºì»¨ TAµÄ»ØÌû
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