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The problem may be in the occupancy of hydrogen. I have already changed the occupancy of hydrogen to 0.5 during building the crystal. However, all the hydrogen atoms always displayed in the unit cell. It looks like a wrong structure. How can I make the hydrogen atoms just show 1/2?

¾§°û²ÎÊý£º
Space group: 63-amam,a=3.693,b=12.22,c=2.865;
Atom positions: Al (0.25,-0.3178,0),O1( 0.25,0.2897,0),O2(0.25, 0.0809,0),1/2 H (0.396,0.038,0).
Structure refs: Clays and clay Minerals, 1981, 29(6):435-445.

Thank you very much.

Leo

[ Last edited by wjqhp on 2010-6-26 at 23:51 ]
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Originally posted by wjqhp at 2010-06-26 23:50:36:
The question has been tetatively solved by the following way:

Change the unit cell to super cell for changing the symmetry of unit cell;
Remove the extraneous H atoms manually;
Find symmetry a ...

0.5ռλµÄ»°ÊÇ×öÁ½¸öÔ­°ûµÄsupercell ,È»ºóÈ¥µôÆäÖÐÒ»¸öÔ­°ûÖеÄH?

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4Â¥2010-06-27 08:49:46
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wjqhp

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The question has been tetatively solved by the following way:

Change the unit cell to super cell for changing the symmetry of unit cell;
Remove the extraneous H atoms manually;
Find symmetry again and impose it to the new structure.
That is all.
QQ£º584473782»¶Ó­·ÃÎÊhttp://leorunfast.wordpress.com
3Â¥2010-06-26 23:50:36
ÒÑÔÄ   »Ø¸´´ËÂ¥   ¹Ø×¢TA ¸øTA·¢ÏûÏ¢ ËÍTAºì»¨ TAµÄ»ØÌû

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ÒýÓûØÌû:
Originally posted by cenwanglai at 2010-06-27 08:49:46:


0.5ռλµÄ»°ÊÇ×öÁ½¸öÔ­°ûµÄsupercell ,È»ºóÈ¥µôÆäÖÐÒ»¸öÔ­°ûÖеÄH?

0.25ռλµÄ»°ÊÇ×öËĸöÔ­°ûµÄsupercell,È»ºóÈ¥µôÆäÖÐÈý¸öÔ­°ûÖеÄH?

ÄÇÕâÑùÊDz»ÊÇûÓбØÒªÉèÖÃoccupancyÁË?Ö±½Ó¸ù¾Ýoccupancy×ösuperc ...

occupancyÖ±½ÓÉèÖÃΪ1£¬È»ºó°ÑÔ­°û¸Ä³Ésupercell,,È¥µôÆäÖжàÓàÔ­×Ó£¬È»ºóÖØÐÂfind symmetry, impose...
ÎÒûÓбðµÄ°ì·¨£¬¾ÍÕâô¸ÉÁË.
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5Â¥2010-06-27 09:05:25
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