| ²é¿´: 1141 | »Ø¸´: 6 | |||
| ¡¾ÐüÉͽð±Ò¡¿»Ø´ð±¾ÌûÎÊÌ⣬×÷Õßzyugiec½«ÔùËÍÄú 100 ¸ö½ð±Ò | |||
| µ±Ç°Ö»ÏÔʾÂú×ãÖ¸¶¨Ìõ¼þµÄ»ØÌû£¬µã»÷ÕâÀï²é¿´±¾»°ÌâµÄËùÓлØÌû | |||
zyugiec¹ÜÀíÔ±
|
[ÇóÖú]
¶¨»ý·ÖÇó½â ÒÑÓÐ3È˲ÎÓë
|
||
|
Ç󶨻ý·Öint((exp(-k3*t))/(Ke*exp(k3*t)+C), t=0,t) ·Ç³£¸Ðл£¬100½ð±ÒÐüÉÍ¡£ |
» ²ÂÄãϲ»¶
¸÷λÀÏʦºÃ£¬ÎÒµÄһ־ԸΪ±±¾©¿Æ¼¼´óѧ085601²ÄÁÏר˶
ÒѾÓÐ12È˻ظ´
359Çóµ÷¼Á
ÒѾÓÐ7È˻ظ´
070300»¯Ñ§×¨Òµ279µ÷¼Á
ÒѾÓÐ10È˻ظ´
»·¾³¹¤³Ì297·ÖÇóµ÷¼ÁÒ»Ö¾Ô¸º¼¸ßÔº
ÒѾÓÐ9È˻ظ´
Ò»Ö¾Ô¸ÎäÀí²ÄÁϹ¤³Ì302µ÷¼Á»·»¯»ò»¯¹¤
ÒѾÓÐ9È˻ظ´
309·Ö085801Çóµ÷¼Á
ÒѾÓÐ5È˻ظ´
Ò»Ö¾Ô¸ ÄϾ©º½¿Õº½Ìì´óѧ £¬080500²ÄÁÏ¿ÆÑ§Ó빤³Ìѧ˶
ÒѾÓÐ5È˻ظ´
²ÄÁϵ÷¼Á
ÒѾÓÐ4È˻ظ´
²ÄÁϵ÷¼Á
ÒѾÓÐ3È˻ظ´
311£¨085601£©Çóµ÷¼Á
ÒѾÓÐ12È˻ظ´
zhengyongyb
¹ÜÀíÔ±
![]()
![]()
![]()
![]()
- Ó¦Öú: 44 (СѧÉú)
- ½ð±Ò: 179.6
- ºì»¨: 3
- Ìû×Ó: 349
- ÔÚÏß: 144.8Сʱ
- ³æºÅ: 1187369
- ×¢²á: 2011-01-11
- ÐÔ±ð: GG
- רҵ: Äý¾Û̬ÎïÐÔ II £ºµç×ӽṹ
¡¾´ð°¸¡¿Ó¦Öú»ØÌû
¸Ðл²ÎÓ룬ӦÖúÖ¸Êý +1
|
û·¨ÌùͼƬ£¬×Ô¼º¸´ÖÆÕ³Ìùµ½¹«Ê½±à¼Æ÷mathtypeÖаɣº \begin{array}{l} \int_{0}^{t} \frac{1}{e^{k_{3} t}\left(K e^{k_{3} t}+C\right)} d t=\frac{1}{C} \int_{0}^{t} \frac{1}{e^{k_{3} t}} d t-\frac{K}{C} \int_{0}^{t} \frac{1}{K e^{k_{3} t}+C} d t \\ \text { ÆäÖÐ }: \frac{1}{C} \int_{0}^{t} \frac{1}{e^{k_{3} t}} d t=-\left.\frac{1}{k_{3} C} e^{k_{3} t}\right|_{0} ^{t}=-\frac{1}{k_{3} C}\left(e^{k_{3} t}-1\right) \\ \text { ¶ø }: \frac{K}{C} \int_{0}^{t} \frac{1}{K e^{k_{3} t}+C} d t=\frac{K}{C} \int_{0}^{t} \frac{e^{-k_{3} t}}{K+C e^{-k_{3} t}} d t=-\frac{K}{k_{3} C^{2}} \int_{0}^{t} \frac{d\left(K+C e^{-k_{3} t}\right)}{K+C e^{-k_{3} t}}=-\frac{K}{k_{3} C^{2}} \ln \mid K+C e^{-k_{3} t} \|_{0}^{t} \frac{1}{K_{3} t}\left(\ln \left|K+C e^{-k_{3} t}\right|-\ln |K|\right) \\ =-\frac{K}{k_{3} C^{2}} \\ \text { ½á¹û }=-\frac{1}{k_{3} C}\left(e^{k_{3} t}-1\right)-\frac{K}{k_{3} C^{2}}\left(\ln \left|K+C e^{-k_{3} t}\right|-\ln |K|\right. \end{array} |
4Â¥2020-11-26 16:01:11
zhengyongyb
¶Ò»»¹ó±ö
![]()
![]()
![]()
![]()
- Ó¦Öú: 44 (СѧÉú)
- ½ð±Ò: 179.6
- ºì»¨: 3
- Ìû×Ó: 349
- ÔÚÏß: 144.8Сʱ
- ³æºÅ: 1187369
- ×¢²á: 2011-01-11
- ÐÔ±ð: GG
- רҵ: Äý¾Û̬ÎïÐÔ II £ºµç×ӽṹ
2Â¥2020-11-26 15:16:48
zhengyongyb
¹ÜÀíÔ±
![]()
![]()
![]()
![]()
- Ó¦Öú: 44 (СѧÉú)
- ½ð±Ò: 179.6
- ºì»¨: 3
- Ìû×Ó: 349
- ÔÚÏß: 144.8Сʱ
- ³æºÅ: 1187369
- ×¢²á: 2011-01-11
- ÐÔ±ð: GG
- רҵ: Äý¾Û̬ÎïÐÔ II £ºµç×ӽṹ
3Â¥2020-11-26 15:23:44
zhengyongyb
ʵϰ°æÖ÷
![]()
![]()
![]()
![]()
- Ó¦Öú: 44 (СѧÉú)
- ½ð±Ò: 179.6
- ºì»¨: 3
- Ìû×Ó: 349
- ÔÚÏß: 144.8Сʱ
- ³æºÅ: 1187369
- ×¢²á: 2011-01-11
- ÐÔ±ð: GG
- רҵ: Äý¾Û̬ÎïÐÔ II £ºµç×ӽṹ
|
\begin{array}{l} \int_{0}^{t} \frac{1}{e^{k_{3} t}\left(K e^{k_{3} t}+C\right)} d t=\frac{1}{C} \int_{0}^{t} \frac{1}{e^{k_{3} t}} d t-\frac{K}{C} \int_{0}^{t} \frac{1}{K e^{k_{3} t}+C} d t \\ \text { ÆäÖÐ }: \frac{1}{C} \int_{0}^{t} \frac{1}{e^{k_{3} t}} d t=-\left.\frac{1}{k_{3} C} e^{k_{3} t}\right|_{0} ^{t}=-\frac{1}{k_{3} C}\left(e^{k_{3} t}-1\right) \\ \text { ¶ø }: \frac{K}{C} \int_{0}^{t} \frac{1}{K e^{k_{3} t}+C} d t=\frac{K}{C} \int_{0}^{t} \frac{e^{-k_{3} t}}{K+C e^{-k_{3} t}} d t=-\frac{K}{k_{3} C^{2}} \int_{0}^{t} \frac{d\left(K+C e^{-k_{3} t}\right)}{K+C e^{-k_{3} t}}=-\frac{K}{k_{3} C^{2}} \ln \mid K+C e^{-k_{3} t} \|_{0}^{t} =\frac{1}{K_{3} t}\left(\ln \left|K+C e^{-k_{3} t}\right|-\ln |K|\right) \\ \text { ½á¹û }=-\frac{1}{k_{3} C}\left(e^{k_{3} t}-1\right)-\frac{K}{k_{3} C^{2}}\left(\ln \left|K+C e^{-k_{3} t}\right|-\ln |K|\right). \end{array} |
5Â¥2020-11-26 16:09:53














»Ø¸´´ËÂ¥