2楼: Originally posted by shenyxtata at 2015-09-15 15:29:42
这是边值问题还是初值问题？

3楼: Originally posted by smowmaple at 2015-09-15 17:38:07
你好，感谢关注！是初值问题。...

4楼: Originally posted by shenyxtata at 2015-09-15 21:31:10
有一整套理论，首先要选显式还是隐式求解法，区别一般数值分析的书都有讲。具体到你这个问题，建议时间步选为2除以某个正整数，这样求解时间t的时候可以用上t-2的解。
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5楼: Originally posted by feixiaolin at 2015-09-16 11:52:26
无耦合项，用拉普拉斯变换处理，最后求反变换
s^2*Y(s)-s*y(0)-y'(0)+s*Y(s)-y(0)+A*=0
s^2*X(s)-s*y(0)-y'(0)+s*X(s)-y(0)+B*=0