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qwbio123
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- ×¢²á: 2012-04-24
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Say you want to make 1 L of 100 mM MES at pH 6.0. The MW of MES (free acid) is 195.2. 1 L at 0.1 mole/L requires 0.1 mole of MES or 19.5 g of MES. Put 19.5 g of MES in something like 500 ml of water, put in a pH electrode (the starting pH will be something below 4.0 probably) and titrate to pH 6.0 with either 1 N or 10 N NaOH. Once you¡¯ve got the solution to the correct pH, transfer it to a graduated cylinder or volumetric flask and dilute it to a final volume of 1 L and you¡¯re done. Different volumes or different desired concentrations of MES will require the use of different amounts os solid MES, but the process will be the same. ÕâÀïÓÐÏêϸµÄ½â´ð¹ØÓÚÈçºÎÅäÖÃ100mmol/L MES»º³åÒºÈçºÎÅäÖÆ£¿£¬ÅäÖúúó¿ÉÒÔ¸ßѹ¸ßÎÂÃð¾ú£¡ |
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