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skydark

木虫 (正式写手)

[求助] 空間群bilbao crystallographic server網站的困擾

bilbao crystallographic server ?W????????
??????????????????g??????  ?? E C2x C2y C2z I ?????
???????ǹ??????????g???? ?o???Bi2Se3 space group no 166 ??? ???? space group no 64
?????īI????????

????и????????????  ??bilbao crystallographic server?e??, ????īI???e?  ???????????e????

Bi2Se3 ?īI :   http://journals.aps.org/prb/pdf/10.1103/PhysRevB.82.045122
????   ?īI :     http://journals.aps.org/prb/pdf/10.1103/PhysRevB.90.115439

bilbao crystallographic server??W?:
http://www.cryst.ehu.es/
??bilbao crystallographic server?????
?c?x Representation Theory Applications??????
REPRES        Space Groups Representations
??? ???x??space group?????Y?^??  64  ??  166, ??? next
????x GM (gamma point) ,  ??????????????°? continue
????????? continue
????????F????g??????

?????īI????  ???l?Fbilbao crystallographic server??????īI???????????
????Bi2Se3??generators ????? E , R3 , R2 , I
??bilbao crystallographic server?@?F????4??generators ?? ??2???@????? R3 (??????3?? E, R2 ,I ???]???})

?????????4??generators ????????????}  
???īI???f?? ?@y?S???D180?????? ???????????translation?????.........

???λ????????n??  ???x!!!
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iamikaruk

木虫 (著名写手)

引用回帖:
5楼: Originally posted by skydark at 2015-02-21 14:25:46
假設是以rhombohedral的lattice vector做為基底的話
那四個generators矩陣應該是這樣:

   E              R3             R2              I
1  0  0      0  1  0       0  -1  0       -1  0  0
0  1  0   ...

我用icsd上的数据,看了下vesta的结果是
hexagonal的是
   1              2               3                4
1  0  0      0 -1  0        0  1  0       -1  0  0
0  1  0      1 -1  0        1  0  0        0 -1  0
0  0  1      0  0  1        0  0 -1        0  0 -1

rhombohedral的是
   E              R3             R2              I
1  0  0      0  1  0       0  -1  0       -1  0  0
0  1  0      0  0  1       -1  0  0        0 -1  0
0  0  1      1  0  0        0  0 -1        0  0 -1

和你的一样。但是我觉得这个应该没有什么问题,rhombohedral axes和hexagonal axes的基矢不一样,对称操作也不一样。
另外我发现你给的PRB文章里面的x和y是基于笛卡尔坐标系,因此你要把它线性变换到hexagonal axes或者rhombohedral axes下,这样对称操作就是一致的了。
[img]http://osu.ppy.sh/stat2/iamikaruk-0.png[/img]
6楼2015-02-21 23:00:21
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iamikaruk

木虫 (著名写手)

因为是hexagonal或rhombohedral的不同吧?
[img]http://osu.ppy.sh/stat2/iamikaruk-0.png[/img]
2楼2015-02-21 02:54:43
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skydark

木虫 (正式写手)

???????:
2?: Originally posted by iamikaruk at 2015-02-21 02:54:43
?????hexagonal??rhombohedral???????

?????????_????????
hexagonal??Bi2Se3??bravais lattice,  rhombohedral ??Bi2Se3??primitive unit cell
????_????????
bilbao crystallographic server?W???o?????D??????????hexagonal??lattice vector?????
3楼2015-02-21 03:56:23
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iamikaruk

木虫 (著名写手)

???????:
3?: Originally posted by skydark at 2015-02-21 03:56:23
?????????_????????
hexagonal??Bi2Se3??bravais lattice,  rhombohedral ??Bi2Se3??primitive unit cell
????_????????
bilbao crystallographic server?W???o?????D??????????hexagonal??latti ...

?????????????????????????????????????rhombohedral??
[img]http://osu.ppy.sh/stat2/iamikaruk-0.png[/img]
4楼2015-02-21 08:14:00
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