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涛涛屈

银虫 (初入文坛)

[求助] 帮忙给我我看看这程序错在哪了?应该怎么改!实在是搞不明白。在此先行表示感谢! 已有1人参与

按照这个程序,for循环想把C逐步变大(C=C+0.05),y_mean=sqrt((L_mean+R_mean-Ca_mean-Cb_mean-Cc_mean-3*C).^2-10000),在C变大的过程中,Y_mean应该要变小才对,为什么程序执行下去,发现还变大了,实在是搞不懂。
clear all
clc
x=1e7;
chou=1e5;
C=0;
for i=0:100000
R_o = normrnd(199.9588,0.1675,[1 1e7]);
L_o = normrnd(399.9615,0.1699,[1 1e7]);
Ca_o = normrnd(0.043,0.0129,[1 1e7]);
Cb_o = normrnd(0.043,0.0129,[1 1e7]);
Cc_o = normrnd(0.043,0.0129,[1 1e7]);
k_R = unidrnd(x,[1,chou]);
k_L = unidrnd(x,[1,chou]);
k_Ca = unidrnd(x,[1,chou]);
k_Cb = unidrnd(x,[1,chou]);
k_Cc = unidrnd(x,[1,chou]);
R_k = R_o(k_R);
L_k = L_o(k_L);
Ca_k = L_o(k_Ca);
Cb_k = L_o(k_Cb);
Cc_k = L_o(k_Cc);
R_mean = mean(R_k);
L_mean = mean(L_k);
Ca_mean = mean(Ca_k);
Cb_mean = mean(Cb_k);
Cc_mean = mean(Cc_k);
y_mean=sqrt((L_mean+R_mean-Ca_mean-Cb_mean-Cc_mean-3*C).^2-10000)
y=sqrt((L_k+R_k-Ca_k-Cb_k-Cc_k-3*C).^2-10000);
k=length(find(y<590));
Pf=1-k/chou
C=C+0.05
if Pf<0.95
    break;
end
end
plot(C,y_mean)
xlabel('间隙大小')
ylabel('滑块最大输出位移平均值/mm')
title('考虑非累积性因素时滑块最大输出位移')
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acalephs

捐助贵宾 (著名写手)

【答案】应助回帖

感谢参与,应助指数 +1
抽选数值的时候抽错数列了,改成下边的试试

R_k = R_o(k_R);
L_k = L_o(k_L);
Ca_k = Ca_o(k_Ca);
Cb_k = Cb_o(k_Cb);
Cc_k = Cc_o(k_Cc);
2楼2015-01-26 16:31:09
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acalephs

捐助贵宾 (著名写手)

【答案】应助回帖

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涛涛屈: 金币+68, ★★★★★最佳答案, 非常感谢,在您这学会了很多东西,祝您事事顺心。 2015-01-27 09:26:13
CODE:
clear all
clc
x=1e7;
chou=1e5;
C=0;
for i=0:100000
R_o = normrnd(199.9588,0.1675,[1 1e7]);
L_o = normrnd(399.9615,0.1699,[1 1e7]);
Ca_o = normrnd(0.043,0.0129,[1 1e7]);
Cb_o = normrnd(0.043,0.0129,[1 1e7]);
Cc_o = normrnd(0.043,0.0129,[1 1e7]);
k_R = unidrnd(x,[1,chou]);
k_L = unidrnd(x,[1,chou]);
k_Ca = unidrnd(x,[1,chou]);
k_Cb = unidrnd(x,[1,chou]);
k_Cc = unidrnd(x,[1,chou]);
R_k = R_o(k_R);
L_k = L_o(k_L);
Ca_k = Ca_o(k_Ca);
Cb_k = Cb_o(k_Cb);
Cc_k = Cc_o(k_Cc);
R_mean = mean(R_k);
L_mean = mean(L_k);
Ca_mean = mean(Ca_k);
Cb_mean = mean(Cb_k);
Cc_mean = mean(Cc_k);
%%
y_mean(i+1)=sqrt((L_mean+R_mean-Ca_mean-Cb_mean-Cc_mean-3*C).^2-10000)
y=sqrt((L_k+R_k-Ca_k-Cb_k-Cc_k-3*C).^2-10000);
k=length(find(y<590));
Pf=1-k/chou
C=C+0.05
if Pf<0.95
    break;
end
end
plot(linspace(0.05,C,length(y_mean)),y_mean)
xlabel('间隙大小')
ylabel('滑块最大输出位移平均值/mm')
title('考虑非累积性因素时滑块最大输出位移')

3楼2015-01-26 16:46:37
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