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y(0) = 0,y¡ä(0) = 1,y(pai/8) = 1
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feixiaolin

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p=y'
p''-2p'+5p=0    p=k1*exp(-(1+2i)t) + k2*exp(-(1-2i)t)
´úÈëÌõ¼þ£¬È·¶¨ k1, k2
2Â¥2014-10-01 07:59:58
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vincentyoung

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ÒýÓûØÌû:
2Â¥: Originally posted by feixiaolin at 2014-10-01 07:59:58
p=y'
p''-2p'+5p=0    p=k1*exp(-(1+2i)t) + k2*exp(-(1-2i)t)
´úÈëÌõ¼þ£¬È·¶¨ k1, k2

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3Â¥2014-10-01 08:18:16
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peterflyer

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feixiaolin: ½ð±Ò+5 2014-10-01 10:23:19
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s^3*U-s^2*0-s*1-a-2*[s^2*U-s*0-1]+5*[s*U-0]=0
[s^3-2*s^2+5*s]*U=s+a-2
U=(s+a-2)/(s^3-2*s^2+5*s)
=(s+a-2)/{s*[(s-1)^2+2^2]}
=A/s+[B*(s-1)+2*C]/[(s-1)^2+2^2]
=A*1/s+B*(s-1)/[(s-1)^2+2^2]+C*2/[(s-1)^2+2^2]
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A=
B=
C=
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5Â¥2014-10-01 09:12:25
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vincentyoung(feixiaolin´ú·¢): ½ð±Ò+2 2014-10-01 10:24:20
ÒýÓûØÌû:
5Â¥: Originally posted by peterflyer at 2014-10-01 09:12:25
½âÕâ¸öÌâĿֻ¸øÎå¸ö½ð±ÒʵÔÚÌ«ÉÙÁË¡£ºÇºÇ¡£

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A=(a-2)/5;B=-(a-2)/5;C=(a+3)/10
y=(a-2)/5-(a-2)/5*e^x*Cos[2*x]+(a+3)/10*e^x*Sin[2*x]
½«y(¦Ð/8) = 1´úÈëÉÏʽ£º
1=(a-2)/5-(a-2)/5*e^(¦Ð/8)/sqrt(2)+(a+3)/10*e^(¦Ð/8)/sqrt(2)
½âµÃ£ºa=7
¹Ê£ºy=1-e^x*Cos(2*x)+e^x*Sin(2*x)
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6Â¥2014-10-01 09:44:29
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