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xffla

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hengxing_001

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RXMCDM: 金币+1 2014-06-09 07:46:45
xffla: 金币+5, 翻译EPI+1 2014-06-09 13:03:15
xffla: 金币+1, 有帮助 2014-06-09 13:04:18
Integrating both sides of Eq. (1) along the height of the beam, and then taking the zeroth moment and first moment, respectively, we can derive,
3楼2014-06-09 05:59:50
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Paulwolf

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RXMCDM: 金币+1 2014-06-09 07:46:52
xffla: 金币+3 2014-06-09 13:04:00
We compute the integral of the heights of each end of the beam, then get its zero order moment and one order moment, respectively. then we get the:
2楼2014-06-08 21:01:47
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peterflyer

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xffla: 金币+4 2014-06-09 13:03:28
To Integrate both sides of equation (1) along the height direction of the beam, then chose the zero and first order moment respectively, we obtain
4楼2014-06-09 07:00:53
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peterflyer

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RXMCDM: 金币+1 2014-06-09 07:46:36
xffla: 金币+2 2014-06-09 13:04:12
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4楼: Originally posted by peterflyer at 2014-06-09 07:00:53
To Integrate both sides of equation (1) along the height direction of the beam, then chose the zero and first order moment respectively, we obtain

To Integrate both sides of equation (1) along the height direction of the beam, then choose the zero and first order moment respectively, we obtain
5楼2014-06-09 07:03:14
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