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RXMCDM: ½ð±Ò+1 2014-06-09 07:46:52
xffla: ½ð±Ò+3 2014-06-09 13:04:00
We compute the integral of the heights of each end of the beam, then get its zero order moment and one order moment, respectively. then we get the:
2Â¥2014-06-08 21:01:47
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RXMCDM: ½ð±Ò+1 2014-06-09 07:46:45
xffla: ½ð±Ò+5, ·­ÒëEPI+1 2014-06-09 13:03:15
xffla: ½ð±Ò+1, ¡ïÓаïÖú 2014-06-09 13:04:18
Integrating both sides of Eq. (1) along the height of the beam, and then taking the zeroth moment and first moment, respectively, we can derive,
3Â¥2014-06-09 05:59:50
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xffla: ½ð±Ò+4 2014-06-09 13:03:28
To Integrate both sides of equation (1) along the height direction of the beam, then chose the zero and first order moment respectively, we obtain
4Â¥2014-06-09 07:00:53
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peterflyer

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RXMCDM: ½ð±Ò+1 2014-06-09 07:46:36
xffla: ½ð±Ò+2 2014-06-09 13:04:12
ÒýÓûØÌû:
4Â¥: Originally posted by peterflyer at 2014-06-09 07:00:53
To Integrate both sides of equation (1) along the height direction of the beam, then chose the zero and first order moment respectively, we obtain

To Integrate both sides of equation (1) along the height direction of the beam, then choose the zero and first order moment respectively, we obtain
5Â¥2014-06-09 07:03:14
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