| ²é¿´: 131 | »Ø¸´: 1 | |||
| µ±Ç°Ö÷ÌâÒѾ´æµµ¡£ | |||
| ¡¾Óн±½»Á÷¡¿»ý¼«»Ø¸´±¾Ìû×Ó£¬²ÎÓë½»Á÷£¬¾ÍÓлú»á·ÖµÃ×÷Õß hygff µÄ 3 ¸ö½ð±Ò | |||
[½»Á÷]
¹ØÓÚʹÓø߷Ö×Ó²ÄÁÏΪÔÁϵķ´Ó¦Öж¨Á¿ÎÊÌâ?
|
|||
|
¸÷λ³æÓѰï°ïæ! ÔÚ½øÐкϳÉʱ,ÈôÔÁÏÊÇÓþۺÏÎï,ÇëÎÊÄãÃǶ¼ÊÇÔõÑù¶¨Á¿µÄ? ÊÇÐèÒªÖªµÀËüµÄ¾ÛºÏ¶È,È»ºóºÍС·Ö×Ó¶¨Á¿ÔÔò(µÈĦ¶û)À´½øÐж¨Á¿Âð? |
» ²ÂÄãϲ»¶
ÉúÎïѧ308Çóµ÷¼Á£¨Ò»Ö¾Ô¸»ª¶«Ê¦´ó£©
ÒѾÓÐ6È˻ظ´
µ÷¼ÁÇóÊÕÁô
ÒѾÓÐ7È˻ظ´
272·Ö²ÄÁÏ×ÓÇóµ÷¼Á
ÒѾÓÐ36È˻ظ´
275Çóµ÷¼Á
ÒѾÓÐ8È˻ظ´
Ò»Ö¾Ô¸211£¬»¯Ñ§Ñ§Ë¶£¬310·Ö£¬±¾¿ÆÖصãË«·Ç£¬Çóµ÷¼Á
ÒѾÓÐ20È˻ظ´
070300»¯Ñ§Ñ§Ë¶311·ÖÇóµ÷¼Á
ÒѾÓÐ19È˻ظ´
²ÄÁÏÓ뻯¹¤µ÷¼Á
ÒѾÓÐ13È˻ظ´
²ÄÁÏÓ뻯¹¤µ÷¼Á
ÒѾÓÐ33È˻ظ´
¸´ÊÔµ÷¼Á
ÒѾÓÐ7È˻ظ´
Ò»Ö¾Ô¸¹þ¹¤´ó 085600 277 12²Ä¿Æ»ùÇóµ÷¼Á
ÒѾÓÐ17È˻ظ´
» ±¾Ö÷ÌâÏà¹ØÉ̼ÒÍÆ¼ö: (ÎÒÒ²ÒªÔÚÕâÀïÍÆ¹ã)
changjiang77
½ð³æ (ÕýʽдÊÖ)
- Ó¦Öú: 5 (Ó×¶ùÔ°)
- ½ð±Ò: 602.2
- ºì»¨: 1
- Ìû×Ó: 338
- ÔÚÏß: 15.1Сʱ
- ³æºÅ: 510333
- ×¢²á: 2008-02-24
- רҵ: µç»¯Ñ§·ÖÎö
depend on what you want to do.
¡ï
ftgsmile(½ð±Ò+1,VIP+0):¶àл²ÎÓë½»Á÷£¬»¶Ó³£À´¾«»¯°æ~~(*^__^*) ¡¡
ftgsmile(½ð±Ò+1,VIP+0):¶àл²ÎÓë½»Á÷£¬»¶Ó³£À´¾«»¯°æ~~(*^__^*) ¡¡
|
1. If you want to do reaction for each unit. You just have to calculate the mol of uniits. Tha's just simple. Treat the unit as small molecules. 2. If you want to do raciton for the end group. OK, you have to calculate the amount of end groups. Then, you will need molecular weight information. So, what is the reaction you want to do? |
2Â¥2008-03-03 04:36:03













»Ø¸´´ËÂ¥
