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1.heat/flux ·½·¨
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Èȵ¼ÂʼÆËãheat/flux ÎÊÌâ-1
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2.thermal/conductivity·½·¨
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[ Last edited by w76990480 on 2013-7-19 at 17:46 ]
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lammpsÊÆº¯Êý²¿·Ö
# set interatomic interactions
set          group   O    charge  -1.14
set          group   Zn   charge   1.14
kspace_style      ewald 1.0e-5
pair_style hybrid/overlay  buck 10.0 coul/long 10.0 morse 10.0
pair_coeff  1 2  buck  257600  0.1396  0.0
pair_coeff  2 2  buck  78.91   0.5177  0.0
pair_coeff  1 1  morse 0.1567  1.164   3.405
pair_coeff  * *  coul/long

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2Â¥2013-07-20 16:11:49
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z654023015

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3Â¥2013-07-21 17:00:37
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w76990480

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ÒýÓûØÌû:
3Â¥: Originally posted by z654023015 at 2013-07-21 17:00:37
ÄãÓ¦¸Ã°ÑÄãµÄinÎļþÌù³öÀ´Ò»Ï£¬»¹°ÑÄã¼ÆËãµÄÌåϵ˵Ã÷°×Ò»µã

Dear lammps users£º
    I have some questions on ZnO thermal conductivity calculation£¬The fix heat/flux and fix thermal/conductivity command were selected to calculating the ZnO thermal conductivity.
    1.fix heat/flux
      I wrote the input file like the manual (http://lammps.sandia.gov/doc/compute_heat_flux.html), the average thermal conductivity of ZnO(Model: x 5.0nm y 4.8nm z 5.3nm) is about ~50W/mk.   The thermal conductivity-m curve you can see the fig 1 in the attachment.
    2.thermal/conductivity
      The periodic boundary wurtzite-type ZnO was selected to calculating thermal conductivity in x y z direction 2.8nm 2.9nm 15.7nm respectively¡£The main command as following£º
      fix      temp_profile all ave/spatial 1 100000 100000 z lower 1.0 v_temp file temp.profile units lattice  #YL for test
      fix      heat_swap all thermal/conductivity 10 z 60
      fix      e_exchange  all  ave/time  10  1  100000  f_heat_swap  file e_exchange.dat
      fix accumu_thermalK_out all ave/time 10 1 100000 v_accumu_thermalK file thermal_conductivity.dat
      I used this ¡°variable accumu_thermalK equal f_e_exchange*${ev2J}/(2*0.001*${N}*${ps2s}*${Ox}*${Oy}*${An2m}*f_delta_out)*(${Oz}/60.0*26.0)¡± variable command to calculating it.
          timestep 0.001
          N        step
      Is it right£¨this variable to calculate the thermal conductivity£©?
      Temperature gradient is linear in the fig 2 (in the attachment). the average thermal conductivity is about 5W/mk.

     Now, Two kinds of method to calculate the thermal conductivity of why have so big difference(The two methods with the same potential)?
רҵÎÄÏ×ÇóÖú
4Â¥2013-07-21 22:00:36
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